Simplify. −6x+8/6−3/2x−1/2+5/2x
2 answers:
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Answer:
He owned Cat for 5 years.
Step-by-step explanation:
Given: Owned dog for 9 years.
Dog owned year is one year less than twice as long as he owned a cat.
Lets assume the years that cat has been owned be "x".
Now, finding the number years that Cat hes been owned.
As given, Dog owned year is one year less than twice as long as he owned a cat.
∴ using equation to find the Cat´s owned years.
⇒
adding 1 on both side.
⇒
dividing both side by 2
⇒
∴x=
Hence, Cat has been owned for 5 years.
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.