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3 years ago

I’m being timed pls help

Chemistry

1 answer:

FinnZ [79.3K]3 years ago

3 0

You have 18 oxygen atoms on one side and (currently) have 6 oxygen atoms on the other.

You can add the coefficient 6 to equal this out!!

Hope this helps :)

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The reaction A + B ⟶ C + D rate = k [ A ] [ B ] 2 A+B⟶C+Drate=k[A][B]2 has an initial rate of 0.0640 M / s. 0.0640 M/s. What wil

Lubov Fominskaja [6]

Answer :

(1) The initial rate when [A] is halved and [B] is tripled is, 0.288 M/s

(2) The initial rate when [A] is tripled and [B] is halved is, 0.096 M/s

Explanation:

The given rate law expression is:

$Rate=k[A][B]^2$

Now we have to determine the initial rate when [A] is halved and [B] is tripled.

The new rate law expression will be:

$Rate=k\times (\frac{[A]}{2})\times (3\times [B])^2$

$Rate=k\times (\frac{[A]}{2})\times 9\times [B]^2$

$Rate=k\times (\frac{9}{2})\times [A]\times [B]^2$

Given:

Initial rate = 0.0640 M/s

As, Initial rate = $k[A][B]^2$ = 0.0640 M/s

Thus,

$Rate=(\frac{9}{2})\times 0.0640M/s$

$Rate=0.288M/s$

Now we have to determine the initial rate when [A] is tripled and [B] is halved.

The new rate law expression will be:

$Rate=k\times (\frac{[B]}{2})^2\times (3\times [A])$

$Rate=k\times (\frac{[B]^2}{4})\times 3\times [A]$

$Rate=k\times (\frac{3}{4})\times [A]\times [B]^2$

Given:

Initial rate = 0.0640 M/s

As, Initial rate = $k[A][B]^2$ = 0.0640 M/s

Thus,

$Rate=(\frac{3}{4})\times 0.0640M/s$

$Rate=0.096M/s$

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3 years ago

Which equation is balanced?

nadya68 [22]

C “2Al + 3F2=2AlF3”

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3 years ago

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In a chemical change molecules DO NOT create or break chemical bonds to form a new substance you might be able to observe a chem

vesna_86 [32]

Answer:

false

Explanation:

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3 years ago

63.5 grams of alcohol having a density of 0.818 g/ml are require for a chemical reaction. How many milliliters of alcohol should

damaskus [11]

Mass = 63.5 grams

density = 0.818 g/mL

D = m / V

0.818 = 63.5 / V

V = 63.5 / 0.818

V = 77.628 mL

hope this helps!

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3 years ago

Of all the Sunny Club members in a particular city, 25% prefer swimming on weekends and 75% prefer swimming on weekdays. 10% of

professor190 [17]

10% of the 25% of people that prefer to swim on weekends are female.

Multiply 10% and 25% to get 0.025

 55% of the 75% are females who prefer to swim on the weekdays.
Multiply them together getting 0.4125

Divide 0.25 by 0.10= 0.40

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3 years ago

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