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dusya [7]
3 years ago
11

What are the ion concentrations in a 0.12 M solution of AlCl3? A) 0.12 M Al3+ ions and 0.040 M Cl- ions B) none of the answers C

) 0.36 M Al3+ ions and 0.12 M Cl- ions D) 0.12 M Al3+ ions and 0.36 M Cl- ions E) 0.040 M Al3+ ions and 0.040 M Cl- ions
Chemistry
1 answer:
KIM [24]3 years ago
5 0

Answer:

D

Explanation:

To answer this question, we will need to write the dissociation equation of aluminum trichloride.

AlCl3 ——-> Al3+ + 3Cl-

It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.

From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same

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A longitudinal wave passing through a medium causes areas of:
torisob [31]

Answer:

The answer is B. Compressions and rarefactions.

Explanation:

  • <u><em>Longitudinal sound waves are waves of alternating pressure deviations from the equilibrium pressure, causing local regions of compression and rarefaction.</em></u>
4 0
2 years ago
When 8.21 l of c3h8 (g) burn in oxygen, how many liters of oxygen are consumed? all gas volumes are measured at the same tempera
just olya [345]
<span>8.21 L of C3H8(g) Lets take c as the molar volume at that temperature.
    c L <><> 5c L
  C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q
  8.21 L <><> x L
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5 0
3 years ago
Whats Potassium bond type? Please help!
olga_2 [115]

Answer:

A metallic bond.

Explanation:

Potassium is a metal (alkali metal), hence its bonds are metallic bonds.

Hope this helped!

5 0
3 years ago
Read 2 more answers
1.5g of magnesium ribbon is burnt in oxygen to produce 2.5g of magnesium oxide. How much oxygen is required in grams?
Furkat [3]

Answer:

2.5 grams

Explanation:

law of conservation of mass applies. the magnesium completely burns

4 0
3 years ago
A box contains a mixture of small copper spheres and small lead spheres. The total volume of both metals is measured by the disp
kirill115 [55]

Answer:44.01% of the spheres are copper

Explanation:

mass Cu + mass Pb = 4.35kg =  4.35 x 1000 = 4350g

But

Volume= mass / density

Let the volume of copper be C  

density of  Cu = 8.94 g/cm^3

Mass of copper = 8.94C

Let the volume of Lead be L  

density of  lead = 11.34g/cm^3

Mass of lead  = 11.34L

Since  

mass Cu + mass Pb = 4350kg

therefore

8.94C + 11.34L = 4350g----- EQN A

also

volume of copper + volume of lead =  423 cm^3

Volume of Lead ,L=423-C

putting the value of C = 423-L in Equation A becomes

8.94C + 11.34L = 4350g

8.94C + 11.34(423-C)= 4350g

8.94C+ 4796.82-11.34C=4350

4796.82-4350=11.34C- 8.94

446.82=2.4C

C= 186.175

Volume of copper = 186.175cm^3

Percentage copper = volume copper / total volume metal x 100/1

= 186.175 cm^3 / 423 cm^3 x 100/1

= 44.01%

3 0
3 years ago
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