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ella [17]
3 years ago
10

PLEASE ANSWER THIS IF YOU HAVE AN OCULUS!!

Physics
1 answer:
yan [13]3 years ago
8 0

Answer:

Ah good question um no u dont have to be near it its a vr thing ur gonna have it on u the whole time. You can only be a few feet away from ur tv if u chose to do it on there or u can do it on ur phone but its also the same distance.

Explanation:

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Change the following data into scientific notation.<br><br> 5 000 000 km
RoseWind [281]
To find out scientific notation, you want to make sure that number is less than 10. So do 5.000000, you don't rally need the zeros but I just want to make my point. So use 10^x meaning ten the whatever power adds zeros like 5.000000x10^6 meaning it is increasing it by six zeros moving it out of the decimals and letting become 5,000,000. 
8 0
3 years ago
What is the wavelength of a photon whose energy is twice that of a photon with a 600 nm wavelength?
bearhunter [10]
Planck's equation states that
E = hf
where
E =  the energy,
h = Planck's constant
f =  the frequency

Because
c = fλ
where
c =  velocity of light,
λ = wavelength
therefore
E = h(c/λ)

Photon #1:
The wavelength is λ₁ = 60 nm.
The energy is
E₁ = (hc)/λ₁

Photon #2:
The energy is twice that of photon #1, therefore its energy is
E₂ = 2E₁ = (hc)/λ₂.

Therefore
\frac{E_{2}}{E_{1}}= \frac{(hc)/\lambda_{2}}{(hc)/60 \, nm} =2\\ \frac{60}{\lambda_{2}} =2 \\ \lambda_{2} =  \frac{60}{2} =30 \, nm

Answer:  30 nm

8 0
3 years ago
Read 2 more answers
Which of the following steps to solve a problem is completed last?
Vesna [10]

Answer:

that would be analyzing data I believe

7 0
3 years ago
Read 2 more answers
Can someone please help me. idk what to do​
Alex_Xolod [135]

Answer:

-4.5 m/s

Explanation:

Even without doing calculations, we know that a projectile has the same speed coming down as it did going up at the same height.  Since it went up at 4.5 m/s, it returns down at -4.5 m/s.

To prove it with math, use the given information:

v₀ = 4.5 m/s

a = -9.8 m/s²

Δy = 0 m

Find: v

v² = v₀² + 2aΔy

v² = (4.5 m/s)² + 2 (-9.8 m/s²) (0 m)

v = -4.5 m/s

3 0
4 years ago
The copper windings of a motor have a resistance of 50 Ω at 20° C when the motor is idle. After the motor has run for several ho
Drupady [299]

Answer:

The temperature of the windings are 60.61 °C

Explanation:

Step 1: Data given

Resistance = 50 Ω

Temperature = 20.0 °C

After the motor has run for several hours the resistance rises to 58Ω.

Step 2: Calculate the new temperature

Formula: R = Rref(1 + α(T-Tref))

⇒with α = temperature coëfficiënt of Cupper at 20 °C = 0.00394/°C

⇒with Tref = reference temperature = 20°C

⇒with T = end temperature = TO BE DETERMINED

⇒with R = resistance at end temperature = 58Ω

⇒with Rref = resistance at reference temperature =  50 Ω

==> T = (R/Rref - 1)/α + Tref  

T = (58/50) - 1 )/ 0.00394 + 20

   T = 60.61 °C

The temperature of the windings are 60.61 °C

5 0
4 years ago
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