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gizmo_the_mogwai [7]

3 years ago

14

The cheetah starts at a position of 0.2 m and ends at a position of 45.6 m. What is the displacement of the cheetah during this

time?

1 answer:

Andreyy893 years ago

8 0

Displacement is equals to final position minus initial position so final position is 45.6 m and initial position is 0.2 m so 45.6 - .2= 45.4

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The term "exfoliation dome" is best applied to ________. the term "exfoliation dome" is best applied to ________. bryce national

BlackZzzverrR [31]

An exfoliation dome is a geological structure wherein it is primarily when the overburden of a surface gets removed by erosion, thus leading to rock relaxation. In addition, the term would be best applied to the national landmark of Yosemite National Park wherein the place has one of the best waterfalls in California.

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4 years ago

Find the length of a microscope having magnifying power 100, if the focal lengths of the objective and eye piece are 2 cm and 5

sp2606 [1]

Answer:

L = 40 cm

Explanation:

A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens

M = - L / f₀ (25 cm / $f_{e}$ )

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L = - M f_{o} f_{e} / 25

let's calculate

L = - (-100) 2 5/25

L = 40 cm

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3 years ago

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3 years ago

A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student

storchak [24]

<u>Answer:</u>

2.39 kg

<u>Explanation:</u>

There is conservation of momentum here in this problem so we will use the following problem:

$m_1u_1+m_2u_2=(m_1+m_2)v$

where the mass of the student $m_1$ is 48.5 kg,

the mass of the skateboard $m_2$ is $m_2$ kg,

the initial speed of the student $u_1$ is 4.25 m/s; and

the speed of the student and skateboard $v$ is 4.05 m/s.

So substituting the given values in the above formula to get:

$(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05$

$206.125=196.425+4.05m_2$

$206.125 - 196.425 = 4.05m_2$

$m_2=\frac{9.7}{4.05}$

$m_2=2.39$

Therefore, the mass of the skateboard is 2.39 kg.

7 0

3 years ago