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3 years ago

Can someone help me please

Mathematics

1 answer:

adelina 88 [10]3 years ago

3 0

Hey I think 4 B it's 5

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GARDEN Amanda is planting flowers in a rectangular garden. She wants to know the amount of space in her backyard the garden will

Andrew [12]

The function A(x) = 2x²-3x-2 represents the area of the garden.

Step-by-step explanation:

Given,

Length of rectangular garden is given by;

L(x) = 2x+1

Width of rectangular garden is given by;

W(x) = x-2

Area of rectangular garden;

A(x) = L(x) * W(x)

$A(x) = (2x+1)(x-2)\\A(x) = 2x(x-2)+1(x-2)\\A(x) =2x^2-4x+x-2\\A(x) = 2x^2-3x-2$

The function A(x) = 2x²-3x-2 represents the area of the garden.

Keywords: Area, rectangle

Learn more about area at:

#LearnwithBrainly

6 0

3 years ago

What are the roots of the polynomial equation x^2+8x-48=0

____ [38]

Given polynomial x^2+8x-48 = 0

x^2+12x-4x-48 = 0

x(x+12)-4(x+12) = 0

(x+12)(x-4) = 0

x+12 = 0

Subtract 12 from each side.

x+12-12 = 0-12

x = -12

and x-4 = 0

Add 4 to each side.

x-4+4 = 0+4

x = 4

Roots are -12,4.

4 0

3 years ago

Find Each product

Law Incorporation [45]

Answer:

2.b

3.a

4.c

Step-by-step explanation:

hope it helps you

5 0

2 years ago

Sammy bought 15.3 Liters of milk. She poured the milk equally into 5 bottles. There was 0.35 liters of milk left over. Calculate

Zanzabum

Answer:

The capacity of milk in 1 bottle is 2.99 liters

Step-by-step explanation:

Let us solve the question

∵ Sammy bought 15.3 liters of milk

∵ She poured the milk equally into 5 bottles

∵ There were 0.35 liters of milk leftover

→ At first, subtract the leftover from the quantity she bought to

find the capacity of the five bottles

∴ The capacity of the 5 bottles = 15.3 - 0.35

∴ The capacity of the 5 bottles = 14.95 liters

→ To find the capacity of each bottle divide the total capacity by 5

∴ The capacity in one bottle = 14.95 ÷ 5

∴ The capacity in one bottle = 2.99 liters

∴ The capacity of milk in 1 bottle is 2.99 liters

8 0

3 years ago

Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,

olganol [36]

ANSWER

No solution

EXPLANATION

The first equation is

$y = {x}^{2} - 2x$

and the second equation is

$y = - 2x - 1$

We equate the two equations to obtain;

${x}^{2} - 2x = - 2x - 1$

This implies that

${x}^{2} = - 2x + 2x - 1$

${x}^{2} = - 1$

There is no real number whose square is -1.

Therefore, the equation has no solution.

6 0

3 years ago

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