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motikmotik
3 years ago
11

What are the coordinates of the midpoint between the points (-1,4) and (2,-5)

Mathematics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

(1/2, -1/2)

Step-by-step explanation:

To find a midpoint add the two x's and divide by 2 so -1+2 / 2 = 1/2

add the two y's and divide by 2 so 4-5 / 2 = -1/2

Put the two numbers together as a coordinate (1/2, -1/2)

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What is 4X -3+ 2X plus one minus X +8
garri49 [273]

Answer:

5x + 6

Step-by-step explanation:

4x - 3 + 2x + 1 - x + 8

= 4x + 2x - x -3 + 1 +8

= 5x + 6

5 0
3 years ago
Read 2 more answers
6x2 - 5x - 4 is equivalent to:
Sophie [7]

Answer:

<em>(</em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em>)</em><em> </em><em> </em><em>(</em><em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>4</em><em>)</em>

Step-by-step explanation:

Solution:

  • 6x² - 5x - 4
  • 6x²- (8 - 3)x - 4
  • 6x²- 8x + 3x - 4
  • 2x (3x - 4) +1 (3x - 4)
  • (2x + 1) (3x - 4)
4 0
2 years ago
Please answer this I will give u​
satela [25.4K]

Answer:

Step-by-step explanation:

The 3 angles must add up to 180. So

6x + 4x + 2x = 180

12x = 180

x = 15

Plug this into all the angles and you have your answers

5 0
3 years ago
Read 2 more answers
Increase 10cm by 20%
solniwko [45]

Answer:

12 cm

Step-by-step explanation:

multiply 10 by .2

10 × .2 = 2

add 2 to 10

2 + 10 = 12 cm

5 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
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