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Furkat [3]
3 years ago
7

Solve the following inequality: 55 – 5q > 4(7–9).

Mathematics
1 answer:
Savatey [412]3 years ago
8 0

Step-by-step explanation:

55 – 5q > 4(7–9)

4(-2)

55- 5q > -8

-5q > -63

q=12.6

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Yuki bought a drop–leaf kitchen table. The rectangular part of the table is a 1–by–5–foot rectangle with a semicircle at each en
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Answer:

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Step-by-step explanation:

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3 years ago
19. A spherical balloon has a circumference of 19cm. what is the approximate surface area of the balloon to the nearest square c
Tamiku [17]
The main formula of a spherical surface area is SA= 4 x Pi x r²
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3 years ago
Find the equation of the line<br> passing through the points 1,-5)<br> and (9,11).<br> y = 2x + [?]
Naily [24]

Answer:

y = 2x - 7

Step-by-step explanation:

Looks like we already have the slope of this line:  It is 2.  Working with the point (1, -5), we have x = 1 and y = -5 and can from this info easily find the y-intercept, b:

y = mx + b becomes

y  = 2x + b, which in turn becomes

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3 0
3 years ago
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Morgarella [4.7K]

Answer:

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8 0
3 years ago
Read 2 more answers
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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