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2 years ago

Pleas help due to night

Mathematics

2 answers:

igomit [66]2 years ago

6 0

Answer:

w = 28.4 yards. Sorry need the points.

Alinara [238K]2 years ago

3 0

Answer:

w = 28.4 yds

Step-by-step explanation:

P = 12.7 + 4 + 2w

73.5 = 16.7 + 2w

56.8 = 2w

w = 56.8/2

w = 28.4

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1. April can complete a project in 3 days and Bob can complete the same project in 6 days.

konstantin123 [22]

It will take three days !!

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2 years ago

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What are the measures of the missing angles x°, y° of a regular triangle if one angle measure equals 60°?

MArishka [77]

Answer:

So each interior angle measurement of the regular triangle is 60 degrees.

Step-by-step explanation:

If the triangle is regular, this means all the side measurements are congruent to each other and that all the angle measurements are congruent to each other.

If the sum of the angles in a triangle is 180 degrees and you know they are each the same then you could either solve x+x+x=180 or know we are just dealings with an equiangular triangle in which all angles have measurement 60 degrees.

If need more convincing, let's actually solve:

x+x+x=180

3x=180

x=180/3

x=60

So each interior angle measurement of the regular triangle is 60 degrees.

3 0

2 years ago

In the triangle above, which angle is smallest in measure?

Setler79 [48]

Angle A because the opposite side is the smallest, the smallest side being 28.49.

8 0

3 years ago

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Gary draws this sequence of patterns of white and grey squares. The sequence is continued. How many grey squares will there be w

zzz [600]

Answer:

20 gray squares

Step-by-step explanation:

Given

See attachment for squares

Required

Number of gray squares when white = 16

First, we calculate the equation that represents both squares.

<u>The white squares</u>

$a = 2$ --- initial

$d = 4 - 2 = 6 - 4$

$d = 2$ -- difference between successive gray squares

So, the nth term is:

$W_n = a + (n - 1)d$

$W_n = 2 + (n - 1)*2$

$W_n = 2 + 2n - 2$

$W_n = 2n$

<u>The gray squares</u>

$a = 6$ --- initial

$d = 8-6=10-8$

$d = 2$ -- difference between successive gray squares

So, the nth term is:

$G_n = a + (n - 1)d$

$G_n = 6 + (n - 1) *2$

$G_n = 6 + 2n - 2$

$G_n = 4 + 2n$

When the white squares is 16

$W_n = 16$ --- Calculate n

$W_n = 2n$

$16 = 2n$

$8 = n$

$n = 8$

To get the number of gray squares;

Substitute $n = 8$ in $G_n = 4 + 2n$

$G_n = 4 + 2 * 8$

$G_n = 20$

4 0

2 years ago

The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma

nata0808 [166]

Answer:

a) $\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b) Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c) $P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d) $P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e) $P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

$X \sim N(110000,40000)$

Where $\mu=110000$ and $\sigma=40000$

If we select a sample size of n =35 the standard error is given by:

$\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b. What is the expected shape of the distribution of the sample mean?

Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c. What is the likelihood of selecting a sample with a mean of at least $112,000?

For this case we want this probability:

$P(X > 112000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d. What is the likelihood of selecting a sample with a mean of more than $100,000?

For this case we want this probability:

$P(X > 100000)$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000

For this case we want this probability:

$P(100000$

And we can use the z score given by:

$z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

8 0

3 years ago

Pleas help due to night​​

Pleas help due to night