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Anni [7]
3 years ago
11

Simplify the expression. Write your answer as a power.

"TexFormula1" title="(5^{4} )^{3}" alt="(5^{4} )^{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

5^{12}

Step-by-step explanation:

Lets say there's a number 'x' and there's an expression (x^a)^b where 'a' & 'b' are also numbers , <u>the simplified form of the expression is </u>x^{a \times b}<u>.</u>

So ,

(5^4)^3 = 5^{4 \times 3} = 5^{12}

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Consider this quadratic equation. 2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?
Mariulka [41]

Answer:

\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}

Step-by-step explanation:

Quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}

x = \frac{3+-7}{4}

Hope this helps and God bless!

6 0
2 years ago
-(3-10y) simplify expression pls
Diano4ka-milaya [45]

Answer:

-3+10y

Step-by-step explanation:

Distribute the Negative.

6 0
3 years ago
Read 2 more answers
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
George has $3 in his saving account. He then adds $4 per day to the account. Let y represent the total amount in the account aft
dusya [7]

Answer:

y = 4x + 3

Step-by-step explanation:

since we know how much he adds daily, we can put it next to 4, since we don't know how long he is going to save money. next you just add 3 as a checkpoint

5 0
3 years ago
Read 2 more answers
50 pts and brainliest for first answer
gavmur [86]

Answer:

An acute angle ("acute" meaning "small") is an angle smaller than a right angle. The range of an acute angle is between 0 and 90 degrees.

An obtuse triangle (or obtuse-angled triangle) is a triangle with one obtuse angle (greater than 90°) and two acute angles. Since a triangle's angles must sum to 180° in Euclidean geometry, no Euclidean triangle can have more than one obtuse angle.

Protractor: an instrument for measuring angles, typically in the form of a flat semicircle marked with degrees along the curved edge.

Degrees: a unit of measurement of angles, one three-hundred-and-sixtieth of the circumference of a circle.

Right Angel: an angle of 90°, as in a corner of a square or at the intersection of two perpendicular straight lines.

Straight Angle: an angle of 180°.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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