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Anni [7]
2 years ago
11

Simplify the expression. Write your answer as a power.

"TexFormula1" title="(5^{4} )^{3}" alt="(5^{4} )^{3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Charra [1.4K]2 years ago
6 0

Answer:

5^{12}

Step-by-step explanation:

Lets say there's a number 'x' and there's an expression (x^a)^b where 'a' & 'b' are also numbers , <u>the simplified form of the expression is </u>x^{a \times b}<u>.</u>

So ,

(5^4)^3 = 5^{4 \times 3} = 5^{12}

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How many different ways can an after school club of 13 students line up?
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Answer:

13! or 6227020800

Step-by-step explanation:

With no restrictions, we can figure out the answer to be 13! by the following analysis:

For the first position in line, there are 13 different students who could fill that spot. If we fill it and proceed to the next position in line, there are now only 12 students left who can fill it, since one is already in line. Then the next position only has 11 possibilities, and the next 10, and so on.

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how many 5-digit even numbers can be formed with the digits 1,2,3,4,5, and 6 if repetition is allowed?​
Setler79 [48]

Given:

The given digits are 1,2,3,4,5, and 6.

To find:

The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).

Solution:

To form an even number, we need multiples of 2 at ones place.

In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.

We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.

Total number of ways to form a 5 digit even number is:

Total=6\times 6\times 6\times 6\times 3

Total=3888

Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.

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