<h3>
Answer: Choice C) x^4 - 2</h3>
Explanation:
If the exponent is negative, then that means we apply the reciprocal. So something like x^(-2) becomes 1/(x^2). A polynomial cannot have a variable in the denominator like this. So we can rule out choices A, B, and D. Choice C is the only thing left. It is a polynomial because the exponent is a positive whole number.
Answer:
she need to pay is $550.40
Step-by-step explanation:
given data
interest = 4.2 % compounded quarterly = 0.042 / 4 = 0.0105
future value = $7000
time = 3 year = 3 × 4 = 12 months
to find out
How much money she need to pay
solution
we will apply here formula for future value for compound quarterly
that is
future value = principal ×
.............1
put here all these value
future value = principal ×
7000 = principal ×
principal = 550.40
so she need to pay is $550.40
Answer:
A. He will have to work 40 hours to buy the headphones
B. 1200 ≤ 10.25x ≤ 2000 where x is # of hrs worked
He can work anywhere between 118 and 196 hours.
Step-by-step explanation:
A. Divide 399.95 by 10.25 to get 39.01 hours. But since you cant work 0.01 of an hour, you have to round up to the next hour
B. You want to make more than or equal to 1200, so put that in the inequality. You want to make less or equal to 2000, so you put that in the inequality. In the middle, you put 10.25 an hour multiplied by the number of hours, which is a variable.
To solve, I made 10.25x = 1200, and x equaled 117.07, which rounds up to 118 hours because you cant work a 0.07 of an hour. 118 hours is the low number of the spectrum.
To solve for the highest number on the spectrum, you do 10.25x = 2000, and x equals 195.12, but since you cant work 0.12 of an hour, it rounds up to 196 hours.
For this case we have that by definition, the density is given by:

Where:
M: It is the mass of the diamond
V: It is the volume of the diamond
According to the data of the statement we have:

So the volume is:

Thus, the volume of the diamond is approximately 
Answer:

Answer:
Step-by-step explanation:
1. Subtraction
2.multiplication