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3 years ago

What are all the elements in a column called? NO LOOKING IT UP and if u do put it in ur words

Chemistry

1 answer:

Aliun [14]3 years ago

7 0

Answer:

There have been seven horizontal rows of elements are called phases in the periodic table of elements. Groups, or families, are called vertical columns of elements. Metals, – anti, and metals are the most common ways of classifying the periodic table.

Explanation:

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4. What is the percent by mass of tungsten in the calcium tungstate compound CaWO3, commonly

MA_775_DIABLO [31]

Answer: 67.4%

Explanation:

Ca 40.8

W. 183.8

O. 16.00

CaWO3 272.6

W = 183.8/272.6 = 0.674

3 0

3 years ago

Convert 8.2 x 1012 nm to miles

pishuonlain [190]

Answer:

5.1563867 × 10-9 miles

hope it helps

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2 years ago

The specific heat of a certain type of metal is 0.128j/(g.c). What is the final temperature if 305.J of heat is added to 72.7g o

expeople1 [14]

E answer is -60.57 = -60.6 KJ.
CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) +C2H2(g) H= -127.2 KJ
Hf C2H2 = 226.77
Hf Ca(OH)2 = -986.2
Hf H2O = -285.83
Now,

add them up. 226.77 - 986.2 + (2*285.83) = -187.77
Add back the total enthalpy that is given in the question
-187.77+127.2 = -60.57

3 0

3 years ago

I don’t need the answers to this but u can if u want but I’m just asking what is this is asking for and how to solve it? I hope

strojnjashka [21]

Answer:

See explanation

Explanation:

Salts are produced from the reaction of an acid and a base. In general ...

Acid + Base => Salt + Weak Electrolyte

Acids from the 'Arrhenius Definition' contain an 'ionizable' hydrogen (-H). Such as, HCl, HBr, HI, HNO₃, HClO₄, HF, etc.

Bases from the 'Arrhenius Definition' contain an 'ionizable' hydroxide (-OH). Such as, LiOH, NaOH, KOH, CsOH, Ca(OH)₂, etc.

When the acid and base react, they proceed by what is known as a 'Double Replacement Reaction' or 'Metathesis Reaction'. In the process, the ions of the reactant compounds exchange positions such that a 'Driving Force' compound is formed on the product side. The Driving Force compound is always on the product side of the equation and is a compound that takes one of three forms => A precipitating salt, a compound of a weak acid or weak base (weaker than the starting acid or base) or gas decomposition product (~ vinegar + backing soda rxn => CO₂ gas).

For your problem, split the compound into cations and anions. You can usually tell which is which by using this format on formulas like those listed in your question => reading formula from left to right, place an imaginary line after the 1st metal => this metal will be the cation & the remaining formula will be the anion.

KBr => K | Br => K (Potassium) is the cation (K⁺) and Br (Bromide) is the anion (Br⁻)

KBr => K⁺ + Br⁻

Now. Apply this rule => Add 'H' to anion => HBr, then add 'OH' to cation => KOH.

HBr is the acid and KOH is the base. Therefore ...

Acid + Base => Salt + Wk Electrolyte

HBr + KOH => KBr + H₂O (note how ions of reactants exchange places to form products).

So, KBr comes from the reaction of acid HBr and base KOH.

HBr + KOH => KBr + H₂O

To determine the acid and base origins of LiCl and NaF, use the same logic. Hope this helps. Doc :-)

7 0

3 years ago

How many moles of potassium nitrate are required to make 550 mL of a 2.1M solution?

stira [4]

Answer:

1.155 moles of potassium nitrate are required to make 550 mL of a 2.1M solution.

Explanation:

In a mixture, the chemical present in the greatest amount is called a solvent, while the other components are called solutes.

Molarity is a unit of concentration of a solution and indicates the amount of moles of solute that appear dissolved in each liter of the mixture. In other words, the Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molatity( M)=\frac{number of moles of solute}{Volume}$

Molarity is expressed in units ( $\frac{moles}{liter}$ ).

In this case:

Molarity= 2.1 M
number of moles of solute= ?
Volume= 550 mL= 0.550 L (being 1L=1000 mL)

Replacing:

$2.1 M= 2.1 \frac{moles}{liter} =\frac{number of moles of solute}{0.550 liters}$

Solving:

number of moles of solute= 2.1 M* 0.550 L

number of moles of solute= 1.155 moles

1.155 moles of potassium nitrate are required to make 550 mL of a 2.1M solution.

4 0

3 years ago