Why should the oil be removed from a low pressure system at 130F

1 answer:

6 0

When removing oil from a low pressure system, the temperature should be 130°F because, less refrigerant will be contained in the oil at higher temperature. Liquid charge into a deep vacuum will boil and may lower temperatures enough to freeze water in the tubes.

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What determines the property of hardness in a mineral?

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Methanol has a normal boiling point of 64.6C and a heat of vaporization of 35.2 kJ/mol. What is the vapor pressure (in Torr) of

DENIUS [597]

Answer:

vapor pressure of methanol at 12.0C = 75.09 torr

Explanation:

Using Clausius Clapeyron equation

, we have that

ln (P2/P1)= (ΔHvap /R) (1/T1 - 1/T2)

Given

At Normal boiling point,

Temperature T1= 64.6°C = 64.6 + 273 = 337.6 K, Pressure,P1 = 1 atm

Heat of vaporization = 35.2 kJ/mol

Changing to J/mol

=35.2 x 1000= 35200 J/mol

Temperature , T2 = 12.0oC = 12 + 273 = 285 K

Using gas constant, R = 8.314 J/mol.K

ln (P2/P1)= -(ΔHvap /R) (1/T1 - 1/T2)

ln (P2/ 1 atm) = (35200 J/mol/ (8.314 J/mol.K) X( 1/337.6 - 1/285)

ln (P2/ 1 atm) =4,233.822 X (0.00296-0.003508)

ln (P2/ 1 atm) = 4,233.822468 x-0.0005466866

ln (P2/ 1 atm)= -2.31457

P2 = e^⁻2.31457 x 1 atm

P2=0.098808atm

= 0.098808atm x760 = 75.09 torr

7 0

3 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

Andrews [41]

The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of $124.2^{o}C$ and a boiling point elevation constant $k_{b} = 0.62 ^{o}C kg mol^{-1}$ . A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at $127.4^{o}C$ . Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.