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OverLord2011 [107]
3 years ago
13

Why should the oil be removed from a low pressure system at 130F

Chemistry
1 answer:
grin007 [14]3 years ago
6 0
When removing oil from a low pressure system, the temperature should be 130°F because, less refrigerant will be contained in the oil at higher temperature. Liquid charge into a deep vacuum will boil and may lower temperatures enough to freeze water in the tubes.
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Cubic centimeter is a unit used to measure<br> A) mass<br> B) area<br> C) weight<br> D) volume
Shalnov [3]
The answer to this is volume.
5 0
3 years ago
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Calculate the pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl .
Nitella [24]

Answer: 7

Explanation:

50 ml 0.125 M KOH = (50 * 0.125) = 6.25 ml 1 M KOH

similarly 50 ml 0.125 M HCl = 6.25 ml 1 M HCl

so KOH will fully neutralize the HCl so the pH of the medium will be 7

H+ + OH- = H2O

so Kw = [H=][OH-]

= [H+]^2 = 10-14

SO [H+] = 10-7

pH = -log [H+]

pH = -log[10-7]

pH = 7

6 0
3 years ago
Why is methanol written as ch3oh instead of ch4o?​
Ahat [919]

Answer: Here comes the role of another formula, which we refer to as the structural formula and that is CH3OH for methanol. The structural formula gives us an additional information that carbon is attached to three hydrogen atoms and one oxygen atom.

3 0
3 years ago
A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and wa
Nataly [62]
A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and water by any filtration or centrifuge, it is a colloid mixture. The colloid consists of large molecules & ultra microscopic particles of a substance that has been dispersed by another substance. 
6 0
3 years ago
If 27.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 32.40 mL of 0.185 M HCl, what is the concentration of the
zhannawk [14.2K]

Given information : Volume of HCl = 32.40 mL

32.40 mL\times \frac{1 L}{1000 mL}

Volume of HCl = 0.0324 L

Concentration of HCl = 0.185 M or 0.185 mol/L (M = mol/L)

Volume of Ca(OH)2 = 27.0 mL

27.0 mL\times \frac{1 L}{1000 mL}

Volume of Ca(OH)2 = 0.027 L

We need to find the concentration of Ca(OH)2.

To find the concentration of Ca(OH)2 we need moles and volume of Ca(OH)2.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 can be calculated using stoichiometry and volume of Ca(OH)2 is already given to us.

Step 1 : Find the moles of HCl using its given volume and concentration.

Moles = Concentration \times Volume in L

Moles = 0.185\frac{mol}{1L}\times 0.0324 L

Moles of HCl = 0.005994 mol HCl

Step 2 : We need to find moles of Ca(OH)2 using mol of HCl with the help of mole ratio.

Mole ratio are the coefficient present in front of the compound in a balanced equation.

Mole ratio of Ca(OH)2 : HCl = 1:2 ( 1 coefficient of Ca(OH)2 and 2 coefficient of HCl)

(0.005994 mol HCl)\times \frac{(1 mol Ca(OH)2)}{(2 mol HCl)}

Moles of Ca(OH)2 = 0.002997 mol Ca(OH)2

Step 3 : Find the concentration of Ca(OH)2 using its moles and volume.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 = 0.002997 mol and volume of Ca(OH)2 = 0.027 L

Concentration (Molarity) = \frac{(0.002997 mol)}{(0.027 L)}

Concentration of Ca(OH)2 = 0.111 mol/L or 0.111 M


4 0
4 years ago
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