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2 years ago

When ethyl ether is heated with excess HI for several hours, the only organic product obtained is ethyl iodide. T/F

Chemistry

1 answer:

Anastasy [175]2 years ago

6 0

Answer:

True

Explanation:

Ethers react with HI to form the corresponding alcohols and alkyl iodides.

Similarly, ethyl ether react with excess of HI to form ethanol and ethyl iodide. But in the excess of HI as mentioned in the question, ethanol too undergoes $S^{N}2$ reaction with HI to form ethyl iodide.

<u>Hence, ethyl iodide is the only product when ethyl ether reacts with excess of HI for several hours.</u>

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Setler [38]

Explanation:

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2 years ago

A solid yellow stripe is to be painted in the middle of a certain highway. If 1 gallon of paint covers an area of p square feet

Zolol [24]

Answer:

440mt/p gallons

Explanation:

We are told that one gallon of paint covers an area of p square feet. Knowing this then, the question becomes how much paint is needed to cover a stripe that is t inches wide and m miles long.

Let us first use the dimensions of the stripe to find how much area that is in square feet. A stripe is rectangular so we will calculate the area as follows:

Area of stripe = width x length

= t inches x m miles (we need to convert both to feet)

= (t inches x 1 ft/12 inches) x (m miles x 5280 ft/1 mi)

=440mt square feet

ow we can find out how much paint will be needed by using ratios

p square feet : 1 gallon

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2 years ago

La precipitación ácida es un agente de?

serg [7]

Answer:

acid precipitation is an agent of

Explanation:

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2 years ago

In which group of the Periodic Table do most of the elements exhibit both positive and negative oxidation states?

Shtirlitz [24]

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2 years ago

Consider the chemical equations shown here.

vichka [17]

P₄0₆ $_{s}$ + 20₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$

Explanation:

The overall equation for the reaction that produces P₄0₁₀ is :

P₄0₆ $_{s}$ + 20₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$

Now let us derive this equation:

Given equations:

P₄ $_{s}$ + 30₂ $_{g}$ ⇒ P₄0₆ $_{s}$ equation 1;

P₄ $_{s}$ + 50₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$ equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

P₄0₆ $_{s}$ ⇒ P₄ $_{s}$ + 30₂ $_{g}$ equation 3

equation 2:

P₄ $_{s}$ + 50₂ $_{g}$ + P₄0₆ $_{s}$ ⇒ P₄0₁₀ $_{s}$ + P₄ $_{s}$ + 30₂ $_{g}$

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

P₄0₆ $_{s}$ + 20₂ $_{g}$ ⇒ P₄0₁₀ $_{s}$

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

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2 years ago