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garik1379 [7]
3 years ago
14

The five-number summary for the number of teams in each of Brad's fantasy football leagues is shown in the following table.

Mathematics
1 answer:
Westkost [7]3 years ago
4 0

Answer:

The correct option is (C) 10.

Step-by-step explanation:

The five-number summary for the number of teams in each of Brad's fantasy football leagues is as follows:

Minimum: 4

<em>Q</em>₁: 7

Median: 10

<em>Q</em>₃: 14

Maximum: 18

The minimum value is the smallest value in the data set.

The first quartile (<em>Q</em>₁) is the value that is less than 75% of the observations.

The median is the middle most value of the data set. It is the value that is less than 50% of the observations.

The third quartile (<em>Q</em>₃) is the value that is less than 25% of the observations.

And the maximum value is the largest value in the data set.

So, the five-number summary suggests that about 50% of Brad's fantasy football leagues have fewer than 10 teams.

Thus, the correct option is (C).

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A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
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Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

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