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krok68 [10]
3 years ago
12

If you roll two fair dice(one black die and one white die) in how many ways can you obtain a sum of at least 3

Mathematics
2 answers:
jasenka [17]3 years ago
8 0
There are 35 ways to get a sum of at least 3 when rolling 2 dice.

Out of the 36 possibilities, the only way to NOT have a sum of at least 3 is by rolling two 1's.
kkurt [141]3 years ago
4 0

Answer: 35

Step-by-step explanation:

When two fair dice are thrown , then the sample space would be :

(1,1), (1,2) , (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2) , (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2) , (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2) , (4,3), (4,4), (45), (4,6)

(5,1), (5,2) , (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2) , (6,3), (6,4), (6,5), (6,6)

The total outcomes = 36

We can see that the only outcome in the sample space has sum less than 3 =(1,1)

Now, the number of outcomes in the sample space having sum at-least 3 = 36-1=35

Hence, the number of ways to obtain a sum of at least 3 = 35

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The width of a rectangle measures 9.7 X -4.7 centimetersAnd the length measures 2.9 X +6.4 cm which expression represents the pe
Ymorist [56]

Answer:

25.2X + 3.4 centimeters.

Step-by-step explanation:

The formula for the perimeter of a rectangle

= 2L + 2W

= 2(L + W)

From the question:

Width of a rectangle (W) = 9.7 X - 4.7 centimeters

Length of a rectangle (L) = 2.9 X + 6.4 centimeters

Imputing it into the formula

2(L + W)

2( 9.7X - 4.7 + 2.9X + 6.4)

2 (9.7X + 2.9X - 4.7 + 6.4)

2( 12.6X + 1.7)

= 25.2X + 3.4 centimeters.

Therefore, the perimeter of the rectangle = 25.2X + 3.4 centimeters.

6 0
3 years ago
A group of students were competing to raise money for a charity; their goal was to raise a total of $300. Philip raised 40% of t
Anna11 [10]
$120 because you multiply 300*40 and get 1200 then divide it to 100 and get $120
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3 years ago
3. Given ABCD ≅ FGHJ and mC = 9x - 7, mH = 5x + 13, find the value of x and the measures of angle C and angle H. Show all work
kondor19780726 [428]

Answers:

x = 5

m∠C = m∠H = 38 degrees

 

 

WORKINGS

 

Given that ABCD ≅ FGHJ

We know that corresponding angles of two congruent quadrilaterals are equal

Therefore,

m∠A = m∠F

m∠B = m∠G

m∠C = m∠H

m∠D = m∠I

 

Given,

m∠C = 9x – 7

m∠H = 5x + 13

 

Since m∠C = m∠H

9x – 7 = 5x + 13

 

Add 7 to both sides of the equation

9x – 7 + 7 = 5x + 13 + 7

9x = 5x + 20

 

Subtract 5x from both sides of the equation

9x – 5x = 5x – 5x + 20

4x = 20

 

Divide both sides of the equation by 4

4x/4 = 20/4

x = 5

 

 

To determine the measures of angle C and angle H

m∠C = m∠H

 

We know that m∠C = 9x – 7

Since x = 5

m∠C = 9(5) – 7

m∠C = 45 – 7

m∠C = 38

 

Therefore, m∠C = m∠H = 38 degrees
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Answer:

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