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Zigmanuir [339]
3 years ago
7

Here is my question ​

Mathematics
1 answer:
lara [203]3 years ago
4 0

Answer:

i think its d

Step-by-step explanation:

it takes away 2 from the negative. number.....and negative 5 is still greater...sorry if its wrong

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15 is 9 more than j translate one step equations and solve
Sonbull [250]

Step-by-step explanation:

J=15-9

J=6

(kdkdkokfkfofkfofoc ignore this part)

7 0
3 years ago
You preform an experiment to determine how many breaths a fish takes per minute. Your experiment yields the following data: minu
Alex777 [14]

Alright, lets get started.

experiment yields the following data: minute 1: 65 breaths; minute 2: 73 breaths; minute 5: 62 breaths

Total number of breaths = 65+73+62 = 200

Total minutes observes = 3 minutes

So, average breaths per minute will be = \frac{200}{3}=66.67

So, the average number of breaths that a fish takes per minute is 66.67.  :    Answer

Hope it will help :)



8 0
3 years ago
Read 2 more answers
Score data from a statewide exam for 10th-graders follows a normal distribution, has a mean of 77, and has a standard deviation
Oduvanchick [21]

Answer:

Below 70.5 because of the 68, 95, and 97.5 rule

Step-by-step explanation:

6 0
4 years ago
Alex is 12 years older than George. Carl is Three times older than Alex The sum of their ages is 68 Find the ratio of George’s a
earnstyle [38]

Ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

<em><u>Solution:</u></em>

Let "a" be the age of Alex

Let "g" be the age of George

Let "c" be the age of Carl

<em><u>Alex is 12 years older than George</u></em>

Therefore,

Age of Alex = 12 + Age of George

a = 12 + g

g = a - 12 ---- eqn 1

<em><u>Carl is Three times older than Alex</u></em>

Age of Carl = 3 x Age of Alex

c = 3a -------- eqn 2

<em><u>The sum of their ages is 68</u></em>

age of Alex + age of George + age of Carl = 68

a + g + c = 68 ----------- eqn 3

<em><u>Substitute eqn 1 and eqn 2 in eqn 3</u></em>

a + a - 12 + 3a = 68

5a - 12 = 68

5a = 12 + 68

5a = 80

a = 16

<em><u>Substitute a = 16 in eqn 2</u></em>

c = 3(16) = 48

c = 48

<em><u>Substitute a = 16 in eqn 1</u></em>

g = 16 - 12 = 4

g = 4

<em><u>Find the ratio of George’s age to Carl’s age to Alex’s age</u></em>

Ratio of George’s age to Carl’s age to Alex’s age = g : c : a

g : c : a = 4 : 48 : 16

Divide the above ratio by 4 to reduce to lowest terms

g : c : a - 1 : 12 : 4

Thus ratio of George’s age to Carl’s age to Alex’s age is 1 : 12 : 4

6 0
3 years ago
AD= 5x and DE= 3x- 2
4vir4ik [10]

3x+2=5x-2

2x=4

x=2    i think is the answer im not sure if i got it right im sorry if i did get it wrong

4 0
3 years ago
Read 2 more answers
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