THIS MAKES ABSOLUTELY NO SENSE PLZZZZ HEEELLLP MEEEE

Mathematics

2 answers:

Maslowich3 years ago

5 0

The pattern goes by one letter
So the pattern would be A C E G I K
The pattern skips one letter

zepelin [54]3 years ago

5 0

Answer:

D. K

Step-by-step explanation:

A B C D E F G H I J K L M… then we compare with the pattern. the pattern is A C E G I. note that after each alphabet, the natural next alphabet in line is skipped like a C after A skipping the B and then E after C skipping the D, and so on. thus, the next in the pattern would be K, and we will skip J. so the pattern goes like this A,C,E,G,I,K,M…

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Tony has two shirts, three pairs of pants, and four sports coats. How many different outfits can Tony create?

Akimi4 [234]

Number of shirts = 2
Pants = 3 * 2 = 6
sport coats = 4

Combination = 2 * 6 * 4 = 48

In short, Your Answer would be 48 different outfits

Hope this helps!

4 0

3 years ago

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5 0

3 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$