Answer:
The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.
Explanation:
Vectors are quantities that have their magnitude and direction .
Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.
The solution can be obtained by applying Pythagoras theorem to
resolve the vectors.
Velocity of jet plane = 425 mi/hr
velocity of air = 40 mi/hr
Resultant of the vectors =![\sqrt[]{425^{2}+40^{2}}=426.87](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B425%5E%7B2%7D%2B40%5E%7B2%7D%7D%3D426.87)
mi/hr
Vector direction =
hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward
The half-meter rule (easy math) is 0.5 meters or 50 centimeters since a meter is 1 meters long, which is equivalent to 100 centimeters. Therefore, we shall apply the 50 cm rule.
A 50 cm rule's center of mass is now 25 cm away.
Additionally, according to the data, the object is pivoted at 15 cm, while the 40 g object is hung at 2 cm from the rule's beginning. Using a straightforward formula, we can compare the two situations: the distance from the pivot to the center of the mass times the mass of the 40 g object divided by 2 cm must equal the distance from the pivot to the center of the mass times mass of the 10 x g object
The result of the straightforward computation must be 52g.
Most simplified version:
the center of mass of the rule is at the 25 cm mark
⇒ 
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#SPJ2
It is generally the brightest compared to the other stars in the constellation.
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