Answer:
The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
Explanation:
Given that,
Relative speed of stick v= 0.96 c
Speed of light 
Proper length of stick = 1 m
We need to calculate the length of the stick
Using formula of length
Put the value into the formula
We need to calculate the time the stick take to move
Using formula of time
Put the value into the formula
Hence, The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
Answer:
The following explanatory section gives an explanation of this question.
Explanation:
- This means that perhaps the bubble moves more than a certain duration throughout the calibration breath meter offers the rate as well as oxygenation consumed inside this cell.
- Inside that respirometer, oscillation of something like the bubble gave a technique of multiplying the quantity of oxygenation that is used by the seedlings mostly through cell membrane breathing.
Answer:
v = 10 V and E = 2 10³ N/C
Explanation:
The electrical potentials and the electric field at one point are related by the expression
ΔV = - ∫ E. dS
Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.
If the potential difference is the most usual that is V = 10 V, the electric field is
s = 0.5 cm = 0.5 10⁻² m
E = ΔV / S
E = 10/0.5 10⁻²
E = 2 10³ N / C
