Solving this using the time, we know that range = horizontal velocity x time of flight
since
there are no horizontal forces acting on the ball, there are no
horizontal accelerations and the initial horizontal velocity of 36 cos
28 will be constant throughout. If we use the correct time of flight given the launch parameters, we have
range = 36 cos 28 x 3.44 s = 109.3 m
Answer:
Explanation:
graph would be a straight line from (0, 0) to (400, 8)
Plot points are
PE = mgh
50(0) = 0 J
50(2) = 100 J
50(4) = 200 J
50(6) = 300 J
50(8) = 400 J
Answer:
The maximum electric power output is 
Explanation:
From the question we are told that
The capacity of the hydroelectric plant is 
The level at which water is been released is 
The efficiency is
0.90
The electric power output is mathematically represented as
Where
is the potential energy at level h which is mathematically evaluated as

and
is the potential energy at ground level which is mathematically evaluated as


So
here 
where V is volume and
is density of water whose value is 
So

substituting values


The maximum possible electric power output is

substituting values

