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Luba_88 [7]
2 years ago
12

Sound can't travel through a

Physics
1 answer:
Stella [2.4K]2 years ago
3 0
B sound cannot travel through empty space which is what a vacuum is considered to be
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A ray of light strikes a smooth surface and is reflected. The angle of incidence is 35°. What can be predicted about the angle o
andreev551 [17]
By the law of reflection which says that the angle of reflection is equal to the angle of incidence, which in other words says, sin x = sin y, it can be said, based on the given that the angle of reflection is also equal to the angle of incidence of 35 degrees
5 0
3 years ago
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Barker is unloading 20kg bottles of water from this delivery truck when one of the bottles tips over and slides down the truck r
Degger [83]
<span>The overall force that is acting on the bottle is gravity. With the incline being 30 degrees the full force of gravity isn't acting on the bottle becuase the ramp isn't allowing the bottle to go straight down. By taking the sin of 30 degrees you find the proportion of gravity that is acting on the bottle to be 4.9 meters per second and the bottle weights 20 kg so the force acting on the bottle is 98 Newtons.</span>
8 0
3 years ago
g the newly launched satellite has a gyroscope inside of it. the gyroscope has a moment of inertia that is 1/10 of that of the r
Ivenika [448]

Answer:

L

Explanation:

For every action, there is an equal and opposite reaction.

As the moment of inertia if the gyroscope is 1/10 of that of the remainder of the satellite, the angular velocity of the satellite will be 1/10 that of the spun up gyroscope and in the opposite direction.

L = Iω

4 0
3 years ago
What speed would a fly with a mass of 0.72 g need in order to have the same kinetic energy as a 1250 kg automobile traveling at
Elena L [17]
Kinetic of automobile

Mass m = 1,250 Kg;         V = 11 m/s

Formula: K.E = 1/2 mV²

               K.E = 1/2(1,250 Kg)(11 m/s)²

               K.E = 75,625 J

Speed required for insect to have the same kinetic energy as automobile

Mass of insect = 0.72 g convert to Kg   m = 7.2 x 10⁻⁴ Kg

K.E = 1/2 mV²  Derive V =?

 V = 2 K.E/m

 V = √2(75,625 J)/7.2 x 10⁻4 Kg

 V = √2.1 x 10⁸ m²/s²

 V = 14,491.34 m/s  (velocity of insect)









5 0
3 years ago
a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m f
goblinko [34]

The effort applied : 200 N

<h3>Further explanation</h3>

Equilibrium rotation

\large {\boxed {\bold {\sum \tau = 0}}

F₁.d₁-F₂.d₂=0

F₁.d₁=F₂.d₂

F₁=500 N

d₁=0.5 m

d₂=1.75-0.5=1.25 m

\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N

5 0
3 years ago
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