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tekilochka [14]

3 years ago

11

Find 61x1,000 annex the zeros to form the product

1 answer:

Rudiy273 years ago

6 0

61 × 1000 = ?

61 × 1 = 61
61 × 10 = 610
61 × 100 = 6100
61 × 1000 = 61000

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Help pls and fast<br> 21x+1+26=28

Naya [18.7K]

X=1/21 that the answer

8 0

3 years ago

Read 2 more answers

What's the midpoint between (1,-7) and (-1,-23)

Alik [6]

Answer: (0,-15)

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Explanation:

Add up the x coordinates to get 1+(-1) = 0. Divide this sum in half to get 0/2 = 0. Therefore the x coordinate of the midpoint is 0.

Repeat for the y coordinates. First add the y coordinates to get -7+(-23) = -30. Then divide that result in half to get -30/2 = -15. So the y coordinate of the midpoint is -15.

Overall, the midpoint is (0,-15).

8 0

2 years ago

Brilliant_brown [7]

Answer:

$\cos(\pi -\theta) = 0.42$

$\cos(2\pi +\theta) = -0.42$

3 0

2 years ago

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

$A=P(1+r)^x$

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

$1000=P(1+r)^0\implies P = 1000$

A = 1900 when x = 1,

$1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9$

Thus, the required function that represents the population after x days,

$A=1900(1+0.9)^x=1900(1.9)^x$

If x = 4,

The number of mosquito after 4 days,

$A=1900(1.9)^4 = 24760.99\approx 24761$

If A = 60,000,

$60000 = 1900(1.9)^x$

$\frac{600}{19}=1.9^x$

Taking log both sides,

$\log(\frac{600}{19})=x\log 1.9$

$\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4$

Thus, there will 60,000 mosquitoes after 5 days.

6 0

2 years ago

Sam sees a rocket traveling straight up at an angle of elevation of 24 degrees. If Sam is located 5 miles from the rocket Launch

julsineya [31]

Given :

Angle of elevation, Ф = 24°.

Distance of Sam from launchpad, D = 5 miles.

To Find :

How high is the rocket.

Solution :

Let, height is h.

We know, tan Ф is given by :

$tan \ \phi=\dfrac{h}{d}\\\\tan \ 24^{\circ}=\dfrac{h}{5}\\\\h = 5\times tan \ 24^{\circ}\\\\h = 2.226 \ miles$

Hence, this is the required solution.

7 0

2 years ago