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Andreyy89
3 years ago
13

HELPP IVE BEEN STUCK ON THIS ONEE I WILL GIVE YOU BRAINLIEST MK SJJSJ.​

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

We know the diameter is 3 inches. We need the radius to find the area. By dividing the dimater by 2, we get the radius of 1.5 inches. The answer is 7 inches squared.

Brainliest would be great.

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Justin has a 2pound bag of Lima beans that he want to divide between 3families.how many pound of Lima beans should each family's
m_a_m_a [10]

Answer:

2/3 lbs

Step-by-step explanation:

2 divided by 3=2/3=2/3

Happy learning!

6 0
3 years ago
Alan and his classmates performed a linear regression analysis on the data set shown below and found that the line of best fit t
stealth61 [152]

Answer:

C. y=\frac{4}{5}x+7

Step-by-step explanation:

Alan and his classmates found that the line of best fit through the data had the equation y=-\frac{5}{4}x+18

The slope of this line is m=-\frac{5}{4}

If a line would intersect this line of best fit at right angles, then the two lines are perpendicular to each other.

The slopes of perpendicular lines are negative reciprocals of each other,

Hence that line must have slope \frac{-1}{-\frac{5}{4}} =\frac{4}{5}

Therefore we look for a line whose slope is \frac{4}{5} from the given options.

That line is the third option y=\frac{4}{5}x+7

5 0
3 years ago
Simplify <br><br> (1/2)^2 -6(2-2/3)
Kruka [31]

Answer:

= −31/4

(Decimal: -7.75)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Suppose that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective. Consider randomly selecting thre
Andrew [12]

Answer:

Step-by-step explanation:

Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.

Probability for any one to be defective as of now is \frac{36}{45} =0.80

a) P(E) = 0.80

b) After I draw we have 35 good ones and 9 defective

P(F/E) =\frac{35}{44} \\=0.796

c) P(G/EF)

This is the probability for iii bulb to be good given I and II are goog.

Once I and ii are good we have 43 bulbs with 34 good ones

P(G/EF) =\frac{34}{43} \\=0.7907

5 0
3 years ago
How do u do 6x32 and 7x29 using distribuative property to solve
Rufina [12.5K]

Answer:

use multiple the numbers to get the co rrect

Step-by-step explanation:

32×6

=192

29×7=203

4 0
3 years ago
Read 2 more answers
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