The answer to this question would be: by producing buffer
The pH of optimal growth of bacteria might be different. Some bacteria can grow in an acid condition called acidophile, other live in base condition called alkaliphiles and the rest live in neutral pH condition called neutrophiles. The bacteria can maintain their internal pH by producing acid, base or buffer. If the surrounding pH is too acid, the bacteria can reduce the H+ concentration by producing base. If the condition is too alkali/base, the bacteria can produce acid by doing fermentation.
An extra chromosome will produce an aneuploidy. It may have severe consequences on the resulting zygote.
<h3>Aneuploidies and chromosome abnormalities</h3>
The term 'chromosome abnormalities' refers to different types of problems that occur in meiosis which are associated with the disjunction of chromosomes.
The most common chromosomal abnormality is called aneuploidy, which means an abnormal number of chromosomes.
Aneuploidy is caused by the presence of an extra or due to the lack (missing) of a chromosome during meiosis.
For example, a trisomy is an aneuploidy due to the presence of an extra chromosome (three copies of the same chromosome instead of two).
Learn more about aneuploidy here:
brainly.com/question/2130641
Answer:
(a) number of strands (n) = time (t) ÷ proportionality constant (k)
(b) The time needed for the bacterial to double its initial size is 3.36 hours.
Explanation:
(a) Let the rate (time) be represented by t and the amount (number) of strands of bacteria be represented by n
t is proportional to n, therefore, t = kn (k is the proportionality constant)
Since t = kn, then, n = t/k
(b) Initial amount of strands = 300
Amount of strands after 2 hours = 300 + (300 × 20/100) = 300 + 60 = 360
k = t/n = 2/360 = 0.0056 hour/strand
Double of the initial size is 600 (300×2 = 600)
Time (t) needed for the bacterial to double its initial size = kn = 0.0056×600 = 3.36 hours
