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Ugo [173]
3 years ago
13

What is the percent increase from 50 to 92

Mathematics
2 answers:
Marianna [84]3 years ago
8 0
92/501.84 is 1.84 so 184%
STALIN [3.7K]3 years ago
3 0
Hey!

To find the percentage increase, you must use this formula:

{(50 - 92 / 50] × 100 = 84%

So, the percent increase from 50 to 92 is: 84%.
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Answer:

92

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A retiree invests $5,000 in savings plan that pays 4% per year. What will the account balance be at the end of the first year ?
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The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

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What is the definition of a prime factor?
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Answer:

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