Answer:
Step-by-step explanation:
I think it’s b correct me if I’m wrong
The answer is: 3.91 inches .
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Note: Volume of cylinder: V = (base area) * (height);
in which: V = volume = 384 in.³ ;
h = height = 8 in. ;
Base area = area of the base (that is; "circle") = π r² ;
in which; "r" = radius;
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Solve for "r" :
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V = π r² * (8 in.) ;
384 in.³ = (8 in.) * (π r²) ;
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Divide EACH SIDE of the equation by "8" ;
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(384 in.³) / 8 = [ (8 in.) * (π r²) in.] / 8 ;
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to get:
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48 in.³ = (π r²) in.² * in. ;
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↔ (π r²) in.² * in. = 48 in.³ ;
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Rewrite this equation; using "3.14" as an approximation for: π ;
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(3.14 * r²) in.² * in. = 48 in.³
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Divide EACH SIDE of the equation by:
"[(3.14)*(in.²)*(in.)]" ; to isolate "r² " on one side of the equation;
(since we want to solve for "r") ;
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→ [(3.14 * r²) in.² * in.] / [(3.14)*(in.²)*(in.)] = 48 in.³ / [(3.14)*(in.²)*(in.)] ;
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→ to get: r² = 48/3.14 ;
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→ r² = 15.2866242038216561 ;
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To solve for "r" (the radius; take the "positive square root" of EACH side of the equation:
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→ +√(r²) = +√(15.2866242038216561)
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→ r = 3.9098112747064475286 ; round to 3.91 inches .
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Answer:
0.48 cm
Step-by-step explanation:
Answer:
- Hannah: 2.11 is a terminating decimal that can be written as 2 11/100. Rational numbers can be expressed as fractions.
Step-by-step explanation:
<u>The answer choices are:</u>
- <u>Gus</u>: 2.11 repeats because there are two 1s.
- <u>Gus</u>: 2.11 is a repeating decimal because it stops.
- <u>Hannah</u>: 2.11 is a rational number because it's a decimal.
- <u>Hannah</u>: 2.11 is a terminating decimal that can be written as 2 11/100. Rational numbers can be expressed as fractions.
<u>The correct one is:</u>
- Hannah: 2.11 is a terminating decimal that can be written as 2 11/100. Rational numbers can be expressed as fractions.
Answer:
The standard deviation is 7.7
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

8 percent of the scores are above 89
This means that X = 89 has a pvalue of 1 - 0.08 = 0.92. So when Z = 89, Z = 1.405.





The standard deviation is 7.7