Perimeter of Parallelogram ABCD: Pp=10 cm
BD=?
Perimeter of triangle ABD: Pt=8 cm
Parallelogram ABCD:
AB=CD=L1
BC=AD=L2
Pp=2(L1+L2)
10 cm=2(L1+L2)
Dividing by 2 both sides of the equation:
(10 cm)/2=2(L1+L2)/2
5 cm=L1+L2
L1+L2=5 cm
Triangle ABD
Pt=AB+BD+AD
8 cm=L1+BD+L2
8 cm=BD+L1+L2
But L1+L2=5 cm, then:
8 cm=BD+5 cm
Solving for BD:
8 cm-5 cm=BD+5 cm+ 5 cm
3 cm=BD
BD=3 cm
Answer: The length of the diagonal BD is 3 cm
1 km = 1000 m.....so 4 km = (4 * 1000) = 4000 m...so she runs 4000 meters per day.
each lap is 400 meters.....4000/400 = 10 laps per day
for 3 days.....(3 * 10) = 30 laps in 3 days
Answer:
option-1
option-2
Step-by-step explanation:
Suppose, we have to find distance between x=a to x=b
so, we get distance
distance = b-a
or we can also write as
distance =|b-a|
or
distance =|a-b|
we are given
the distance between 1.8 and 9.4 on the number line
we can write distance as
distance =|9.4-1.8|
distance =|1.8-(9.4)|
so, option-1 and option-4......Answer
Circumference = diameter x pi
Find the diameter:
75.36 = diameter x pi
Divide both sides by pi:
Diameter = 75.36/3.14 = 24 inches.
Area = pi x r^2
R = 1/2 diameter = 12
Area = 3.14 x 12^2
Area = 452.16 in^2
The answer is D.
S = (HR(Wi - Wn)) / 1000.
First, multiply both sides by 1000.
1000S = HR(Wi - Wn)
Divide bot sides by H(Wi - Wn)
(1000S) / H(Wi - Wn) = R