Answer:
- 2/5x=7/20x+1/4
- -3/4=-1/20x-1/2
- -3/4+1/20x=-1/2
Step-by-step explanation:
If you add 3/4 to both sides of the equation, you get ...
... 2/5x = 7/20x + 1/4 . . . . first choice
If you subtract 2/5x from both sides of the equation, you get ...
... -3/4 = -1/20x -1/2 . . . . third choice
If you subtract 7/20x from both sides of the equation, you get ...
... -3/4 +1/20x = -1/2 . . . . last choice
Choices 2 and 4 are erroneous versions of choices 1 and 3, so do not apply.
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer: 25/100* 88
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
To see if (2,0) works as a solution to the systems of equations, we plug in the values of x and y and simplify. If the results are equal, then (2,0) is a solution.
3x + y = 6:
- (2,0) is a solution to this equation.
3x - y = 6:
-
- (2,0) is a solution to this equation.
Therefore, the answer is yes, it does work as a solution.
Have a lovely rest of your day/night, and good luck with your assignments! ♡
Answer:
The number of standard deviations from $1,158 to $1,360 is 1.68.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The number of standard deviations from $1,158 to $1,360 is:
This is Z when X = 1360. So
The number of standard deviations from $1,158 to $1,360 is 1.68.
