Answer:
a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %
Step-by-step explanation:
a. This is a binomial probability.
Let q = probability of giving out wrong number = 15 % = 0.15
p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75
For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹
= 10(0.15)(0.75)⁹
= 1.5(0.0751)
= 0.1126
= 11.26 %
b. At most one wrong is P(x ≤ 1) = P(0) + P(1)
= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹
= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹
= 0.0563 + 0.01126
= 0.06756
= 6.756 %
≅ 6.76 %
Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.
Answer:
x = - 2, x = 7
Step-by-step explanation:
Given
f(x) = 4x² - 20x - 56
To find the zeros let f(x) = 0, that is
4x² - 20x - 56 = 0 ( divide through by 4 )
x² - 5x - 14 = 0 ← in standard form
(x - 7)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x - 7 = 0 ⇒ x = 7
Answer:
50 kg
Step-by-step explanation:
Given that:
SMALL HELICOPTERS:
Weight of small helicopters = 3kg
Weight of shipping container = 20kg
LARGE HELICOPTERS:
Weight of large helicopters = 4kg
Weight of shipping container = 10kg
Number of helicopters each shipping container can hold = s ; all of the packed containers will have the same shipping weight
Shipping weight :
(Weight per helicopter * number of helicopter) + weight of shipping container
Shipping weight of Small helicopters :
(3kg * s) + 20
Shipping weight Large helicopters :
(4kg * S) + 10
Shipping weight of Small helicopters = shipping weight of large helicopters
3s + 20 = 4s + 10
20 - 10 = 4s - 3s
10 = s
Hence, member of shipped helicopters = 10
Total shipping weight :
(4 * S) + 10
(4*10) + 10
40 + 10 = 50kg
Answer:
that is the solution to the question
