C) a solid lower part and a liquid upper part
Explanation:
The physical nature of the earth's core is made up of a solid lower part and a liquid upper part.
The core is the innermost part of the earth and it is made up of metallic minerals.
- It has the highest temperature and pressure of all the layers of the earth.
- The core is divided into two. Outer and inner core.
- Outer core is made up of molten metallic minerals. It is the layer where the earth geomagnetic field originates.
- The inner core is solid metallic ball.
- Evidence from seismic waves has furnished geoscientists with this knowledge.
learn more:
Crust brainly.com/question/10537829
#learnwithBrainly
Answer:
Water droplets acts as tiny prism in the sky. The sunlight when enters these tiny droplets undergo internal reflection and also refract these rays which are dispersed causing a band of seven colors called rainbow.
Explanation:
Answer:

Explanation:
Torque,
is given by
where F is force and r is perpendicular distance
where
is the angle of inclination
Torque,
can also be found by
where I is moment of inertia and a is angular acceleration
Therefore, Fr=Ia and F=mg where m is mass and g is acceleration due to gravity
Making a the subject,
and already I is given as
hence
Taking g as 9.81,
is given as 37 and L is 1.2
Answer:
19.2*10^6 s
Explanation:
The equation for time dilation is:

Then, if it is observed to have a life of 6*10^6 s, and it travels at 0.95 c:

It has a lifetime of 19.2*10^6 s when observed from a frame of reference in which the particle is at rest.
Answer:
1.) 274.5v
2.) 206.8v
Explanation:
1.) Given that In one part of the lab activities, students connected a 2.50 µF capacitor to a 746 V power source, whilst connected a second 6.80 µF capacitor to a 562 V source.
The potential difference and charge across EACH capacitor will be
V = Voe
Where Vo = initial voltage
e = natural logarithm = 2.718
For the first capacitor 2.50 µF,
V = Vo × 2.718
746 = Vo × 2.718
Vo = 746/2.718
Vo = 274.5v
To calculate the charge, use the below formula.
Q = CV
Q = 2.5 × 10^-6 × 274.5
Q = 6.86 × 10^-4 C
For the second capacitor 6.80 µF
V = Voe
562 = Vo × 2.718
Vo = 562/2.718
Vo = 206.77v
The charge on it will be
Q = CV
Q = 6.8 × 10^-6 × 206.77
Q = 1.41 × 10^-3 C
B.) Using the formula V = Voe again
165 = Vo × 2.718
Vo = 165 /2.718
Vo = 60.71v
Q = C × 60.71
Q = C