Suppose that Clayton Kershaw of the Los Angeles Dodgers throws his fastball with a mean velocity of 94 miles per hour (mph) and
a standard deviation of 2 mph and that the distribution of his fastball speeds can be modeled by a Normal distribution What percent of Kershaw’s fastballs will travel at least 100 mph?
ah, probability, so the std. deviation is 2 MPH, so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations or 6 MPH to hit 100
99.7% of throws fall into that area of with in 3 std. deviations so that means
0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast
your equation shown above is set up incorrectly in order to solve this i need the right equation you must plug in each number to q to find the right solution
