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castortr0y [4]
2 years ago
15

Suppose that Clayton Kershaw of the Los Angeles Dodgers throws his fastball with a mean velocity of 94 miles per hour (mph) and

a standard deviation of 2 mph and that the distribution of his fastball speeds can be modeled by a Normal distribution What percent of Kershaw’s fastballs will travel at least 100 mph?
Mathematics
1 answer:
vekshin12 years ago
8 0

Answer:

Step-by-step explanation:

ah,  probability,  so the std. deviation is 2 MPH,  so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations  or  6 MPH to hit 100

99.7%  of throws fall into that area of with in 3 std. deviations so that means

0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast

so

0.15%  will be 100 or faster.... not many

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A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
Im pretty bad with coordinates anyone wanna help with an explanation and and answer please? Ty ​
Salsk061 [2.6K]

Answer:

About 9.4

Step-by-step explanation:

64+25=89

sqr root of 89 is 9.4339

4 0
3 years ago
Please help me no one even bothers to help so plzzzz i BEGGGGGGGGGGG
user100 [1]

Answer:

Here's what I get.

Step-by-step explanation:

When you dilate an object by a scale factor, you multiply its coordinates by the same number.

If the scale factor is 4, the rule is (x, y) ⟶ (4x, 4y)

Your table then becomes

\begin{array}{lcl}\textbf{Vertices of}& \, & \textbf{Vertices of}\\\textbf{VWXY}& \, & \textbf{V'W'X'Y'}\\V(-1 ,1) & \quad & V'(-4, 4)\\W(-1, 2) & \quad & W'(-4, 8)\\X(2, -1) & \quad & X'(8 ,-4)\\Y(2, 2) & \quad & Y'(8, 8)\\\end{array}

The diagram below shows figure VVXY as a green bow-tie and its image V'W'X'Y' in orange.

The scale factor is greater than one, so the dilation is an enlargement.

7 0
3 years ago
What is the slope of a line that is perpendicular to the line whose equation is 0.52 - 5y = 9?
otez555 [7]
The slope is 0.1
To find a perpendicular slope, find the negative reciprocal.
The reciprocal of 0.1 is 10
The negative of 10 is -10
Final answer:-10
7 0
3 years ago
Which expression is equivalent to 7/10-2/10
ki77a [65]

Solution:

we have been asked to find

The expression is equivalent to 7/10-2/10

we can simplify the given expression as below

\frac{7}{10}-\frac{2}{10}=\frac{7-2}{10}\\ \\ \Rightarrow \frac{7}{10}-\frac{2}{10}=\frac{5}{10}\\ \\ \text{Simplify we get}\\ \\ \frac{7}{10}-\frac{2}{10}=\frac{1}{2}\\

Hence the simplified expression , equaivalent to the given expression is 1/2.

4 0
3 years ago
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