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Answer: The coordinates of triangle A'B'C',
A'≡(3/2, -9/4)
B'≡(-3, 9/4)
C'≡(3/2, 9/4)
Step-by-step explanation:
Since, the rule of transforming the triangle ABC by the scale factor -3/4,
Thus, the coordinates of the transformed triangle A'B'C',
So, the coordinates are A'≡(3/2, -9/4)
B'≡(-3, 9/4)
C'≡(3/2, 9/4)
Answer:
46−5y
Step-by-step explanation:
5(10−y)−4
Use the distributive property to multiply 5 by 10−y.
50−5y−4
Subtract 4 from 50 to get 46.
46−5y
Graph if needed:
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and
are the perpendicular bisectors of
and
respectively and they intersect side
at points
and
respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ =
°
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
