2 years ago

Simplify using factorising 2x+4/x^{2}-x-6

Mathematics

1 answer:

Nutka1998 [239]2 years ago

6 0

Answer:

$\frac{2x+4}{x^{2}-x-6 } \\\frac{2x+4}{x^{2} +2x-3x-6} \\\frac{2x+4}{x(x+2)-3(x+2)} \\\frac{2x+4}{(x-3)(x+2)}$

Step-by-step explanation:

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Hey there,

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2 years ago

You are given g(x)=4x^2 + 2x and

Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

$g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt$

Find:

$f(6)$

First, find f(x):

$f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2$

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3 years ago