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xeze [42]
3 years ago
6

Cuántos moles de hipoclorito de sodio (NaCIO)se generan cuando reaccionan 5 moles de NaOH​

Chemistry
1 answer:
Lisa [10]3 years ago
5 0

Answer:

5 mol NaOH = 5 mol NaClO

Plantear y balancear reacción: NaOH + HClO ⇒ NaClO + H2O

Como se puede apreciar, los coeficientes estequiométricos son uno por lo tanto, la cantidad de NaClO que se genera será igual a la cantidad de moles que reaccionan de NaOH

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HELPP ANSWERSSS!!!!
julsineya [31]

Answer:

C.  Cs, because it has the lower ionization energy and more easily gives up its valence electrons to participate in a reaction.

Explanation:

The Cs will produce the most hydrogen gas because it has a lower ionization energy and more easily gives up its valence electrons to participate in the reaction.

  • Ionization energy is the energy required to remove the most loosely held electrons in an atom.
  • Atoms with lower ionization energy readily goes into reactions.
  • This is because they will present little barrier for the reaction to occur.
4 0
3 years ago
Complete and balance the equation for this single-displacement reaction. Phases are optional. Li+NaOH-->
sdas [7]
The complete and <span>balanced equation for this single-displacement reaction would be written as follows:

</span><span>Li+NaOH--> LiOH + Na

In this reaction, lithium replace sodium in the compound sodium hydroxide forming lithium hydroxide and sodium metal as products. Hope this answers the question.</span>
6 0
4 years ago
Read 2 more answers
When 2.499 g of AX (s) dissolves in 135.3 g of water in a coffee-cup calorimeter the temperature rises from 23.6 °C to 35.2 °C.
Elena L [17]

Answer:

The enthalpy change for the solution process \Delta H_{rxn} = - 158.34 kJ/mol

Explanation:

Given that:

The mass of salt AX = 2.499 g

The mass of water = 135.3 g

The mass of the solution = ( 2.499 + 135.3 ) g = 137.799 g

The specific heat of salt solution s is known to be = 4.18 J/g° C

The change in temperature i.e. ΔT = 35.2 °C -  23.6 °C = 11.6 °C

Thus, the amount of heat raised is equal to the heat absorbed by the calorimeter.

∴

q_{reaction} = q_{solution}

q_{reaction} = -ms_{solution} \Delta T

q_{reaction} = -137.799 \ g \times 4.18 \dfrac{J}{g^0C}\times 11.6^0C

q_{reaction} = - 6682 \ J

q_{reaction} = - 6.682 \ kJ

Recall that the mass of the salt = 2.499 g

The number of moles of the salt = 2.499 \ g \times \dfrac{1 \ mol  \ of  \ AX}{59.1097 \ g}

= 0.0422 mol of AX

Finally the enthalpy change, \Delta H_{rxn} =  \dfrac{- 6.682 \ kJ}{ 0.0422 \ mol}

= - 158.34 kJ/mol

The enthalpy change for the solution process \Delta H_{rxn} = - 158.34 kJ/mol

3 0
3 years ago
Why are changes in phase physical changes?
ehidna [41]
Weathering and chemical substance weathering
3 0
3 years ago
. Use the following reaction to determine how much of each product would be released if 42 000 kg (42 tonnes) of methyl isocyana
fenix001 [56]

The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg

<h3>Stoichiometric problem</h3>

From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.

Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles

Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles

Equivaent mole of carbon dioxide = 736.84/2 =368.42moles

Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg

Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

5 0
2 years ago
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