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PtichkaEL [24]
3 years ago
9

Consider the chemical reaction below.

Chemistry
2 answers:
nignag [31]3 years ago
6 0

Answer:

A

Explanation:

because we have 2 charges in other Zn to balance the equation we must give the other Zn 2e

stiks02 [169]3 years ago
4 0

Answer: 2H^++2e^-\rightarrow H_2(g)

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

For the given reactio:

Zn(s)+2H^+\rightarrow Zn^{2+}+H_2

On reactant side:

Oxidation state of zinc= 0

Oxidation state of hydrogen = +21

On product side:

Oxidation state of zinc = +2

Oxidation state of hydrogen = 0

The oxidation state of hydrogen reduces from +1 to 0, it is getting reduced. Thus, it is getting reduced and it undergoes reduction reaction

Hence, the correct answer is 2H^++2e^-\rightarrow H_2(g)

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AgC2H3O2 is: Silver acetate

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Oxyacids contains at least one h+ and an oxyanion. the " sulfurous " oxyacid contains the oxyanion ________.
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What are the advantages and disadvantages of living in a group?
Feliz [49]
Advantages
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3 0
3 years ago
Oxygen always has an oxidation number of -2 unless it is combined with fluorine or found in the compound peroxide. When in the c
Tpy6a [65]

When oxygen is found is peroxide, it has an oxidation number of -1.

The chemical formula of hydrogen peroxide is H2O2. We know that hydrogen always has +1 oxidation state until it forms metal hydrides. So in H2O2, the oxidation state ofhydrogen is +1.

Now, let oxidation state of oxygen be x. So,

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6 0
3 years ago
Please answer ASAP!!
Alenkasestr [34]

Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

<h3>C.0.28 V </h3>

<h3 />

4 0
3 years ago
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