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frez [133]
2 years ago
7

2. What group is Ballardium located? (Bu) *

Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
5 0

Answer:

This question appears incomplete

Explanation:

There is no such element known as "Ballardium (Bu)" in the periodic table. However, there are elements with a bit of similarity in spellings and pronunciation such as Beryllium (Be) which is found in group 2 (meaning it is an alkali earth metal), Berkelium (Bk) which is an actinide (meaning it is radioactive) and Vanadium (V) which is found in group 5 of the periodic table (meaning it's a transition metal).

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Balance chemical reaction of oxalic acid with conc. sulphuric acid​
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Answer:

Explanation: since oxalic acid is a weak acid it wont provide a strong acidic medium. So in order to provide a strong acidic medium dilute sulphuric acid is added.

3 0
2 years ago
which gas law would you use to calculate the new pressure for a gas when the volume of the trapped gas changes while the tempera
meriva
Answer: Boyle's Law

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7 0
3 years ago
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Which of the following will reduce copper?<br> zinc<br> mercury<br> fluorine<br> chlorine
laiz [17]
Zinc because the only metals that would be able to reduce copper ions in solution would be hydrogen, lead, tin, nickel, iron, zinc, aluminum, Magnesium, sodium, calcium, potassium, and lithium. and according to your answer choices Zinc is the answer.
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3 years ago
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What is a property of a substance?
S_A_V [24]

Answer:

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Explanation:

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8 0
2 years ago
A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm
Vsevolod [243]

 The  total pressure  = 1.402 atm


<u><em>calculation</em></u>

Total  pressure = partial  pressure  of gas A + partial pressure of gas B +  partial pressure  of third gas

partial  pressure  of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm


partial pressure for third gas is calculated using ideal  gas equation

that is PV=nRT   where,

p(pressure)=? atm

V(volume) = 8.65 L

n(moles)= 0.200 moles

R(gas constant)=0.0821 L.atm/mol.k

T(temperature) = 11°c into kelvin =11+273 =284 k

make  p the subject of the formula by  diving both side by V

p =nRT/v


p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm



Total  pressure  is therefore = 0.205 atm +0.658 atm +0.539 atm

=1.402 atm

6 0
3 years ago
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