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sasho [114]
3 years ago
7

Where is an object's center of gravity?

Physics
1 answer:
bonufazy [111]3 years ago
7 0

The center of gravity (CG) location is the average location of all the weights of an object. The center of gravity is the balance point of an object, also expressed as the point where all the mass appears to be located.

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A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A horizontal force of 2.5 N is applied o
Masja [62]

Answers is  F=7.84 N

Friction force resists the effect of horizontal force and trying to approch to a limiting force.

we have formula for limiting friction force between block and floor

               F=Ц N

where N=mg

putting values we get answer.

Download pdf
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3 years ago
The process by which you group things based on their similarities is known as classifying.
dusya [7]
True. Classifying by similarities is the basis for biological classification.
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3 years ago
Dimension of density <br>​
Rom4ik [11]

Answer:

See the explanation below.

Explanation:

We know that density is defined as the relationship between mass and volume.

Ro = m/V

where:

m = mass [kg]

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Therefore Ro is given in:

[kg/m^{3} ]

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2 years ago
20 points<br> Which BEST replaces the question mark?<br><br> In Saudi Arabia, __________?
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3 0
3 years ago
a hunter 412.5m from a cliff moves a distance x towards the cliff and fires a gun. he hears the echo from the cliff after 2.2sec
Inessa [10]

Answer: 49.5 m

Explanation:

The speed of sound s is given by a relation between the distance d and the time t:

s=\frac{d}{t} (1)

Where:

s=330 m/s is the speed of sound in air (taking into account this value may vary according to the medium the sound wave travels)

d=412.5 m-x since we are told th hunter was initially 412.5 meters from the cliff and then moves a distance x towards the cliff

t=\frac{2.2 s}{2}=1.1 s Since the time given as data (2.2 s) is the time it takes to the sound wave to travel from the hunter's gun and then go back to the position where the hunter is after being reflected by the cliff

Having this information clarified, let's isolate d and then find x:

d=st (2)

412.5 m-x=(330 m/s)(1.1 s) (3)

Finding x:

x=49.5 m This is the distance at which the hunter is from the cliff.

3 0
3 years ago
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