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postnew [5]
3 years ago
14

How long will it take the cart to to travel 2.8m, starting from rest?

Physics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

0.748seconds

Explanation:

s = 1/2 *g*t^2

2.8 = 1/2 * 10* t^2

5.6 = 10 * t^2

0.56 = t^2

t = √0.56

t = 0.7483seconds

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jamal is playing with magnetic toy vehicles. He has two identical magnetic vehicles (purple and green) on different sides of a c
KengaRu [80]

Answer:

Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.  The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.

Explanation:

Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.

5 0
2 years ago
Janelle stands on a balcony, two stories above Michael. She throws one ball straight up and one ball straight down, but both wit
antoniya [11.8K]

Answer:

Both balls have the same speed.

Explanation:

Janelle throws the two balls from the same height, with the same speed. Both balls will have the same potential and kinetic energy. Energy must be conserved. When the balls pass Michael, again they must have the same potential and kinetic energy.

4 0
3 years ago
A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p
Semenov [28]

Answer:

f_n=3.75N

Explanation:

From the question we are told that:

Frictional force F=0.150N

Coefficient of kinetic friction \mu=0.04

Generally the equation for Normal for is mathematically given by

 f_n=\frac{F}{\mu}

Therefore

 f_n=\frac{0.150}{0.04}

 f_n=3.75N

5 0
2 years ago
Se deja caer una moneda desde cierta altura. Si se desprecian los efectos del aire, ¿cómo varía la fuerza neta sobre la moneda a
forsale [732]

Answer:

Ok, primero pensemos en una situación normal.

La moneda comienza a caer, pero la moneda esta inmersa en una sustancia, el aire. El aire comienza a aplicar una resistencia al movimiento de la moneda, y esta resistencia incremente a medida que la velocidad de la moneda incremente. Llega un punto en el que esta nueva fuerza es igual a la fuerza gravitatoria, y en sentido opuesto, lo que causa que la fuerza neta sea 0, y que la moneda caiga a velocidad constante hasta que esta impacta con el suelo.

Ahora, en este caso tenemos que ignorar los efectos del aire, entonces no hay ninguna fuerza que se oponga a la fuerza gravitatoria, entonces la fuerza neta no cambia a medida que cae (La fuerza neta cambia cuando la moneda impacta el suelo).

También se puede analizar el caso en el que, como la fuerza gravitatoria decrece con el radio al cuadrado, a medida que la moneda cae, la fuerza gravitatoria incrementa. El tema es que en para estas dimensiones, ese cambio en la fuerza gravitacional es imperceptible,

3 0
3 years ago
Can a metallic sphere be charged without rubbing​
morpeh [17]
We need to charge a metal sphere positively without touching it. This can be achieved using electrostatic induction.
6 0
3 years ago
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