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Delvig [45]
3 years ago
8

Make the following conversion

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

The value of 60.2 mg in to g is 0.0602.

Explanation:

We need to calculate the 60.2 mg in to gram.

Conversion mg to g :

1 g = 1000 mg

Using this conversion,

1 mg = 10^{-3}g

So, 60.2\ mg = 60.2\times10^{-3}\ g

60.2\times10^{-3}\ g

Hence, The value of 60.2 mg in to g is 0.0602.

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Consider the motion of a 4.00-kg particle that moves with potential energy given by U(x) = + a) Suppose the particle is moving w
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Correct question:

Consider the motion of a 4.00-kg particle that moves with potential energy given by

U(x) = \frac{(2.0 Jm)}{x}+ \frac{(4.0 Jm^2)}{x^2}

a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?

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a) 3.33 m/s

b) 0.016 N

Explanation:

a) given:

V = 3.00 m/s

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b) magnitude of force when x = 5.0m

u(x) = \frac{-2}{x} + \frac{4}{x^2}

\frac{-du(x)}{dx} = \frac{-d}{dx} [\frac{-2}{x}+ \frac{4}{x^2}

= \frac{2}{x^2} - \frac{8}{x^3}

At x = 5.0 m

\frac{2}{5^2} - \frac{8}{5^3}

F = \frac{2}{25} - \frac{8}{125}

= 0.016N

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Answer:

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There are two different types of reflection:

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