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3 years ago

Make the following conversion

Physics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

The value of 60.2 mg in to g is 0.0602.

Explanation:

We need to calculate the 60.2 mg in to gram.

Conversion mg to g :

1 g = 1000 mg

Using this conversion,

$1 mg = 10^{-3}g$

So, $60.2\ mg = 60.2\times10^{-3}\ g$

$60.2\times10^{-3}\ g$

Hence, The value of 60.2 mg in to g is 0.0602.

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A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how h

Aloiza [94]

$v_x=16,9\frac{m}{s}\\
s=44m\\
g=10\frac{m}{s^2}\\\\
v_x=\frac{s}{t}\Rightarrow t=\frac{s}{v_x}\\\\
t=\frac{44}{16,9}\\\\
t=2,6s\\\\
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3 years ago

The tires of a car make 75 revolutions as the car reduces its speed uniformly from 95 km/hr to 55 km.hr. the tires have a diamet

sveta [45]

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3 years ago

A 10.0g piece of copper wire, sitting in the sun reaches a temperature of 80.0 C. how many Joules are released when the copper c

Zolol [24]

Answer:

150.8 J

Explanation:

The heat released by the copper wire is given by:

$Q=mC_s \Delta T$

where:

m = 10.0 g is the mass of the wire

Cs = 0.377 j/(g.C) is the specific heat capacity of copper

$\Delta T=40.0 C - 80.0 C=-40.0 C$ is the change in temperature of the wire

Substituting into the equation, we find

$Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J$

And the sign is negative because the heat is released by the wire.

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3 years ago

newton's second law states that when a net force acts on an object, it accelerates it.Explain how it would be possible for two o

Alika [10]

Answer:

See Explanation

Explanation:

According to Newton's second law of motion, the acceleration of a body is proportional to the net external force that acts on the body.

A body accelerated when it is acted upon by an unbalanced net external force.

When the external forces acting on a body are balanced, the effect of each force is cancelled by the other hence the body is not accelerated according to Newton's second law.

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2 years ago

The first law of thermodynamics can be given as ________.

MrRa [10]

The first law of thermodynamics can be written as
$\Delta U = Q-W$
where
$\Delta U$ is the variation of internal energy of the system
$Q$ is the amount of heat absorbed by the system
$W$ is the work done by the system on the surrounding.

Using this form, the sign convention for Q and W becomes:
Q > 0 --> heat absorbed by the system (because it increases the internal energy)
Q < 0 --> heat released by the system (because it decreases the internal energy)
W > 0 --> work done by the system (for instance, an expansion: when the system expands, it does work on the surrounding, and so the internal energy decreases, this is why there is a negative sign in the formula Q-W)
W < 0 --> work done by the surrounding on the system (for instance, a compression: when the system is compressed, the surrounding is doing work on the system, and so the internal energy of the system increases)

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3 years ago