Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Answer:
Equation Form: x=−2,y=−2
Step-by-step explanation:
Eliminate the equal sides of each equation and combine.
3/2x+1=−x−4
Solve 3/2x+1=−x−4
for x. x=−2
Evaluate y when x=−2.
y=−2
The solution to the system is the complete set of ordered pairs that are valid solutions.
(−2,−2)
The result can be shown in multiple forms.
Point Form:
(−2,−2)
Equation Form:
x=−2,y=−2
This is your answer: x= -1/4 or x=5/4. Plze mark me brainiest:)
You first set it up as long division.
Second you would find out how many times 6 goes into 67, so count by 6's until you get close 67.
Third once you get that number you write it on top of the long division and then you would subtract whatever that number is below which is 66 because 6 * 11= 66.
So then you would subtract 67 minus 66 which would be 1. Then go from there and you'll get your answer.
Hope this helps!
Answer: B
Explanation: ONE triangle can be formed.
According to the triangle inequality theorem, the sum of any two sides must be greater or equal than the length of the third side.
Here, the sides are 1 m, 2 m, and 2m. 1m + 2m = 3m > 2m (theorem followed) 2m + 2m = 4m > 1m (theorem followed)
Since, the triangle inequality theorem is followed, Hence, ONE triangle can be formed.
