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3 years ago

Can someone solve 8 = b - 1 + 8b STEP BY STEP PLEASE

Mathematics

1 answer:

andrew11 [14]3 years ago

7 0

Answer:

8 = b - 1 + 8b

group like terms

8 + 1 = b + 8b

9 = 9b cus b standing alone me 1b

divide both side by 9

9 = 9b

9 9

b = 1

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Which values of x make the inequality 1 + 5 x < −9 true?

Charra [1.4K]

Answer:

x<-2

Step-by-step explanation:

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3 years ago

Read 2 more answers

Help plz which one is it?

Alina [70]

The answer is A

Reasoning;

a1 = first term;
an= an-1 + d
In a sequence you add the first term (a1) with the second term in a repeating linear equation. In this one you need to add 4 to each term so, the equation is;

a1 = 2
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3 years ago

F(x)= x+4; D: {-5, -3, 0, 4}

Vika [28.1K]

Step-by-step explanation:

-5+4=-1

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3 years ago

DedPeter [7]

Answer:

The solution is (3/8, -7/8).

Step-by-step explanation:

y = −5x + 1

y = 3x − 2

Since the 2 expressions in x are both equal to y :

−5x + 1 = 3x - 2

-5x - 3x = -2 - 1

-8x = -3

x = 3/8.

So y = 3x - 2

= 3(3/8) - 2

= 9/8 - 2 = -7/8.

6 0

3 years ago

Ap calc multiple choice question; attached below please explain how, please!

anygoal [31]

Answer:

C. $\frac{f(b)-f(1)}{b-1}=20$

General Formulas and Concepts:

Calculus

Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that $f'(c)=\frac{f(b)-f(a)}{b-a}$

MVT is also Average Value

Step-by-step explanation:

Step 1: Define

$f(x)=e^{2x}$

f'(c) = 20

Interval [1, b]

Step 2: Check/Identify

Function [1, b] is continuous.

Derivative [1, b] is continuous.

∴ There exists a c∈[1, b] such that $f'(c)=\frac{f(b)-f(a)}{b-a}$

Step 3: Mean Value Theorem

Substitute: $20=\frac{ f(b)-f(1)}{b-1}$
Rewrite: $\frac{ f(b)-f(1)}{b-1}=20$

And we have our final answer!

5 0

2 years ago