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The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76, ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].
About a Graphed Function
The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.
It is evident from the attached graph that the supplied function exceeds 0 for the following range:
-0.7 < F(x) < 0.76
And, 0.76 < F(x) < ∞
As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,
(-0.7, 0.76) and (0.76, ∞)
Learn more about a graphed function here:
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Use this systems of equations to solve:
x = first antifreeze
y = second antifreeze
Isolate y.
x + y = 15
Subtract x from both sides.
y = -x + 15
Substitute y into the other equation.
.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25
Substitute x in the equation that we isolated y in.
y = -11.25 + 15
y = 3.75
11.25 L of the first antifreeze and 3.75 L of the second.
x = first antifreeze
y = second antifreeze
Isolate y.
x + y = 15
Subtract x from both sides.
y = -x + 15
Substitute y into the other equation.
.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25
Substitute x in the equation that we isolated y in.
y = -11.25 + 15
y = 3.75
11.25 L of the first antifreeze and 3.75 L of the second.