Answer:
For C1, Q = 1.6125×10⁻³ C
For C2, Q = 6.25×10⁻⁴ C
Explanation:
Note: Since the capacitors are connected in parallel, The voltage across each of them is equal.
From the question,
Q = CV........................ Equation 1
Where Q = Charge on the capacitor, V = Voltage across the capacitor, C = Capacitance of the capacitor.
For the first capacitor,
Q = C1V............. Equation 2
Where C1 = 6.45 μF= 6.45×10⁻⁶ F, V = 250 V
Substitute into equation 2
Q = (6.45×10⁻⁶ )(250)
Q = 1.6125×10⁻³ C.
For the the second capacitor,
Q = C2V............. Equation 3
Given: C2 = 2.50 μF = 2.5×10⁻⁶ F, V = 250 V
Q = (2.5×10⁻⁶ )(250)
Q = 6.25×10⁻⁴ C
Answer:
option A
Explanation:
given,
lamp position from pool wall = 2.5 m
height of the pool = 2.5 m
now,
from the triangle
θ = i = 45°
using Snell's law
n₁ sin i = n₂ sin r
n₁ =4/3 n₂ = 1
now,
r = sin⁻¹(0.9428)
r = 70.5°
hence, the correct answer is option A
A solution is a homogeneous mixture such as salt water
Answer:
b. horizontal distance/time graph
Explanation:
d is incorrect because object is moving at the same pace the entire time
