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Keith_Richards [23]
3 years ago
10

An insulated lamp bulb is on the bottom of a swimming pool at a point 2.5 m from a wall; the pool is 2.5 m deep and filled to th

e top with water (n = 4/3). At what angle is light refracted out of the water at the edge of the pool?A. 70.5° B. 25.1° C. 40.9° D. 30.4° E. 64.8°

Physics
1 answer:
pashok25 [27]3 years ago
8 0

Answer:

option A

Explanation:

given,

lamp position from pool wall = 2.5 m

height of the pool = 2.5 m

now,

tan \theta = \dfrac{P}{B}

\theta =tan^{-1}(\dfrac{2.5}{2.5})

\theta =45^0

from the triangle

θ = i = 45°

using Snell's law

n₁ sin i = n₂ sin r

n₁ =4/3     n₂ = 1  

now,

\dfrac{sin r}{sin i}=\dfrac{n_1}{n_2}

\dfrac{sin r}{sin 45^0}=\dfrac{\dfrac{4}{3}}{1}

sin r=\dfrac{1}{\sqrt{2}}\times \dfrac{4}{3}

r = sin⁻¹(0.9428)

r = 70.5°

hence, the correct answer is option A

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An ideal gas Carnot cycle with air in a piston cylinder has a high temperature of 1200 K and a heat rejection at 400 K. During t
lana [24]

Answer:

The specific heat capacity is q_{L}=126.12kJ/kg

The efficiency of the temperature is n_{TH}=0.67

Explanation:

The p-v diagram illustration is in the attachment

T_{H} means high temperature

T_{L} means low temperature

The energy equation :

q_{h} = R* T_{h} in(V_{2}/V_{1})

   =0.287 * 1200 ln(3)

   =0.287*1318.33

   =378.36kJ/kg

The specific heat capacity:

q_{L}=q_{h}*(T_{L}/T_{H})

q_{L}=378.36 * (400/1200)

q_{L}=378.36 * 0.333

q_{L}=126.12kJ/kg

The efficiency of the temperature will be:

n_{TH}=1 - (T_{L}/T_{H})

n_{TH}=1-(400/1200)

n_{TH}=1-0.333

n_{TH}=0.67

4 0
2 years ago
The third floor of a house is 8m above street level. How much work is needed to move a 136kg refrigerator to the third floor?
jonny [76]

m = Mass of the refrigerator to be moved to third floor = 136 kg

g = Acceleration due to gravity by earth on the refrigerator being moved = 9.8 m/s²

h = Height to which the refrigerator is moved  = 8 m

W = Work done in lifting the object

Work done in lifting the object is same as the gravitational potential energy gained by the refrigerator. hence

Work done = Gravitation potential energy of refrigerator

W = m g h

inserting the values

W = (136) (9.8) (8)

W = 10662.4 J



8 0
2 years ago
A chef fills 50ml container with 43.5 g of cooking oil. what is the density of the oil?
Rama09 [41]

Answer:

0.87 g per ml

Explanation:

D=M/V

43.5/50=0.87

3 0
2 years ago
During an experiment, a scientist places a heat lamp above a bowl of water and uses the lamp to heat up the water. How does heat
alexandr402 [8]

Answer:

radiation

Explanation:

6 0
2 years ago
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After driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average
belka [17]

We will define the Total mass to calculate the force, so our values are:M_p = 69*27=1823Kg\\M_g=15*3=45Kg\\M_c=3*5=15Kg\\M_B=25Kg

Total Mass = 1863+45+15+25=1948Kg

The Weight is,

F=mg=1948*98=19090.4N

Through the hook's Law we calculate X.

F_s=Kx, where x is the lenght of compression and K the Spring constant.

We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)

X = \frac{F_s}{x} \\X = \frac{1909.4}{k}

I assume a value of K=4*10^4N/m

X= \frac{1909.4}{4*10^4} = 0.48m

6 0
3 years ago
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