It reacts because of the substances against if
Answer:
The distance and average speed are 54.79 m and 10.85 m.
Explanation:
Given that,
Speed = 21.7 m/s
Time = 5.05 s
(a). We need to calculate the distance
Firstly we will find the acceleration
Using equation of motion
Where, v = final velocity
u = initial velocity
t = time
Put the value in the equation
Now, using equation of motion again
For distance,
The distance is 54.79 m.
(b). We need to calculate the average speed during this time
Where, D = total distance
T = time
Put the value into the formula
Hence, The distance and average speed are 54.79 m and 10.85 m.
Answer:
D
Explanation:
5 Km=5000m
so Δv=5000 m/sec
a=Δv/Δt
=5000/10
a=500 m/sec² as 500÷1000=0.5 Km
a=0.5 km/sec²
so D is the right answer.
The momentum would be 9 kg
Answer:
17.1
Explanation:
The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m
The initial speed with which the ranger was driving, u = 11.4 m/s
The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)
The distance required for the ranger to come to rest, s = Required
The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;
v² = u² + 2·a·s
∴ s = (v² - u²)/(2·a)
Where;
v = The final velocity = 0 m/s (the vehicle comes to rest (stops))
Plugging in the values for 'v', 'u', and 'a', gives;
s = (0² - 11.4²)/(2 × -3.8) = 17.1
The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).
