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wolverine [178]
3 years ago
9

You are walking toward the back of a train that is moving forward with a constant velocity. The train's velocity relative to the

ground is 30 m/s forward. Your velocity relative to the train is 1.5 m/s backward. How fast are you moving relative to the ground?
Physics
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

28.5 m/s

Explanation:

There are 2 different velocities: the train velocity and yours velocity. They're in opposite directions, so one is positive and other is negative. Take the forward direction as the positive:

V = +30 -1.5

V = 28.5 m/s

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What four regions of the electromagnetic spectrum
MArishka [77]
There are a lot.
Some of them are

Gamma radiation
X-ray radiation
Ultraviolet radiation
Visible radiation
Infrared radiation
Microwave radiation
6 0
3 years ago
PLS HELP How much power is used if an athlete lives a 100n Weight up 5m in 20 seconds
BlackZzzverrR [31]

Answer:

25J

Explanation:

power = work done ÷ time taken.

and work done = force applied × distance covered.

according to the question, the athlete lifts the weight of 100N upto 5m therefore;

100N × 5m = 500N/m

then onwards,

the work done (500 N/m) should be divided by the time taken to calculate the power,

500 ÷ 20s = 25J

is your answer.

hope this helped. :)

8 0
3 years ago
Read 2 more answers
A 70.0 kg sprinter starts a race with an acceleration of 2.00 m/s2. If the sprinter accelerates at that rate for 29 m, and then
andrey2020 [161]

Answer:

t = 12.82s

Explanation:

F = m×a

  = (70)×(2)

  = 140 N

during the acceleration, the sprinter cover d = 29 m with time:

d = 1/2×at

29 = 1/2×(2)×t^2

t^2 = 29s

t = 5.39s

and attains the velocity of:

v = a×t

  = 2×5.39

  = 10.77 m/s

Then,to cover the last x = 80 m with a speed of 10.77 m/s in time:

t = x/v

 = 80/10.77

 = 7.43s

Therefore, it will take the sprinter 7.43 + 5.39 = 12.82s

6 0
3 years ago
How does light energy work
OLEGan [10]

Answer:

Light consists of photons, which are produced when an object's atoms heat up. Light travels in waves and is the only form of energy visible to the human eye.

Explanation:

6 0
3 years ago
Read 2 more answers
A horizontal 745 N merry-go-round of radius
Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is  544J

Explanation:

Given :

Weight w = 745 N

Radius r =  1.45 m

Force =  56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62  = ?

Solution:

Step 1:  Finding the Mass of merry-go-round

m = \frac{ weight}{g}

m = \frac{745}{9.81 }

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I =0.5 \times m \times r^2

Substituting the values

Moment of Inertia of solid cylinder I  

=>0.5 \times 76.02 \times (1.45)^2

=> 0.5 \times 76.02\times 2.1025

=> 79.91 kg.m^2

Step 3: Finding the Torque applied T

Torque applied T = F \times r

Substituting the values

T = 56.3  \times 1.45

T = 81.635 N.m

 Step 4: Finding the Angular acceleration

Angular acceleration ,\alpha  = \frac{Torque}{Inertia}

Substituting the values,

\alpha  = \frac{81.635}{79.91}

\alpha = 1.021 rad/s^2

 Step 4: Finding the Final angular velocity

Final angular velocity ,\omega = \alpha \times  t

Substituting the values,

\omega = 1.021 \times  3.62

\omega = 3.69 rad/s

Now KE (100% rotational) after 3.62s is:

KE = 0.5 \times I \times \omega^2

KE =0.5 \times 79.91 \times 3.69^2

KE = 544J

6 0
4 years ago
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