Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
Answer:
LCM of 3, 5, and 6 is the smallest number among all common multiples of 3, 5, and 6. The first few multiples of 3, 5, and 6 are (3, 6, 9, 12, 15 . . .), (5, 10, 15, 20, 25 . . .), and (6, 12, 18, 24, 30 . . .) respectively. There are 3 commonly used methods to find LCM of 3, 5, 6 - by division method, by prime factorization, and by listing multiples.
Step-by-step explanation:
Answer: what is the question to this?
Step-by-step explanation: thanks let me know okay
Answer: 12 hours
Step-by-step explanation: 6 h = 360 min,9 h = 540 min, 12 h = 720 min
640-360=280 , 640-540=100 , 640-720=-80
