The empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass is
.
<h3>What is the empirical formula?</h3>
An empirical formula tells us the relative ratios of different atoms in a compound.
We need to calculate the number of moles
Number of a mole of carbon =
48.6 g X (
) =4.05 mole
Number of a mole of hydrogen =
8.2g X (
) =8.14 mole
Number of moles of sulphur =
43.2g X (
) = 1.35 mole
Dividing each mole using the smallest number that is divided by 1.35 moles.
Carbon=
=3
Oxygen=
=6
Sulfur=
=1
Empirical formula is 
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We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
From the question we are told
If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A
Generally the equation for the Concentration Volume relationship is mathematically given as

Therefore
You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
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Answer : The value of
for
is
.
Solution : Given,
Solubility of
in water = 
The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.
The equilibrium equation is,

Initially - 0 0
At equilibrium - s s
The Solubility product will be equal to,
![K_{sp}=[Ba^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BBa%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)

![[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%3D%5BCO%5E%7B2-%7D_3%5D%3Ds%3D4.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL)
Now put all the given values in this expression, we get the value of solubility constant.

Therefore, the value of
for
is
.
4.
Medial collateral ligament, which runs along inside of the knee.
Lateral collateral ligament, which runs along the outside of the knee.
Ligament, which runs in the middle part of the knee.
Posterior cruciate ligament, which works together with the Anterior cruciate ligament.