The given chemical reaction is:
Δ
∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine = 
= 1.20 mol 
Heat change when 1.20 mol chlorine reacts
= 
INFORMATION:
Is given that:
- if you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes.
And after the 10 minutes copper has a higher temperature.
We must determine the reason.
STEP BY STEP EXPLANATION:
To determine it, we need to know the concept of specific heat
If the block of copper has a higher temperature after 10 minutes, that means copper needs less heat to raise its temperature.
So, plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly.
ANSWER:
The explanation for the copper having a higher temperature after 10 minutes in the sun, is that plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly. Since the copper has a lower specific heat, it will be heat quickly.
Answer:
B it has increased slightly
Explanation:I took the test
1)Na and O - ion bond
2)K and F - ion bond
3)Ne and O - no bond (as Ne is a noble gas)
And by elimination, your answer is 4)
Answer: Please see explanation column for answer.
Explanation: For A two-component mixture containing 1-octene and 1, 4-dimethylbenzene with acetone.
Error----- The retention factor (Rf) is 0.95 and the two spots are coming simultaneously together producing only one spot indicating that that the choice of solvent we have used is too polar. The compounds are interacting rapidly with the very polar solvent and have very low interaction with the stationary phase. than the mobile phase.
Solution:-----, We will need to try other low polar solvent that can allow two spots to be formed on the TLC plate eg is the use of different percentage s of hexane in ethyl acetate ether 10% or 20%.
