What is m A.18<br> B.54<br> C.126<br> D.108

Hayley so 20 tickets to the school play for total of $225. Early bird tickets were $10 regular priced tickets are $15. Wright an

alexandr402 [8]

System of Equations

For the problem to solve we'll use the following variables:

x = number of the early bird tickets sold

y = number of the regular tickets sold

Haley sold a total of 20 tickets, thus:

x + y = 20 [1]

Early bird tickets cost $10 and regular tickets cost $15, thus the total money collected is:

10x + 15y = 225

Dividing by 5:

2x + 3y = 45 [2]

We have to solve the system of equations [1] and [2].

Multiply [1] by -2:

-2x - 2y = -40 [3]

Add [3] to [2]:

-2x - 2y +2x + 3y = -40 + 45

Simplifying:

y = 5

Substituting in [1]:

x + 5 = 20

Subtracting 5:

x = 20 - 5

x = 15

Solution: Hayley sold 15 early bird tickets and 5 regular-priced tickets

The order pair solution is (15,5)

5 0

1 year ago

What are the zeros of the function f(x) = x4 − x2 − 2?

goblinko [34]

Answer:

x = ± $\sqrt{2}$ , x = ± i

Step-by-step explanation:

f(x) = $x^{4}$ - x² - 2

to find the zeros , equate f(x) to zero , that is

$x^{4}$ - x² - 2 = 0

using the substitution u = x² , then

u² - u - 2 = 0 ← in standard form

(u - 2)(u + 1) = 0 ← in factored form

equate each factor to zero and solve for u

u - 2 = 0 ⇒ u = 2

u + 1 = 0 ⇒ u = - 1

convert u back into terms of x

x² = 2 ( take square root of both sides )

x = ± $\sqrt{2}$

x² = - 1 ( take square root of both sides )

x = ± $\sqrt{-1}$ = ± i

8 0

1 year ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

2 years ago

Read 2 more answers

What is the vertex of (x) = –16x² + 64x + 80.

cricket20 [7]

Answer:

Step-by-step explanation:

f(x) = a(x - h)² + k - the vertex form of the equation of the parabola with vertex (h, k)

$f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}$

<u>The vertex is </u><u>(2, 124)</u>

7 0

3 years ago

Look at picture. Tell me what G(x)=?

kari74 [83]

The answer is 3 :) hope helps

8 0

2 years ago

Read 2 more answers

What is m A.18 B.54 C.126 D.108