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3 years ago

Classify the following as either a discrete random variable or a continuous random variable.

Mathematics

1 answer:

taurus [48]3 years ago

4 0

Answer: continuous random variable.

Step-by-step explanation:

A discrete random variable is defined as a random variable which consists of countable number. Examples include numbers of shoes, number of sales etc.

A continuous random variable is a random variable whereby the data can take several values. It is a random variable that takes time into consideration.

Therefore, the amount of time six randomly selected volleyball players play during a game will be a continuous random variable since time so involved.

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Over the course of a lifetime about how much more does a college graduate earn than someone who does not have a college degree

Dmitry [639]

C or 750,000 because lol thats just what it is, you can look it up

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4 years ago

Find the unit rate. Round to the nearest hundredth, if necessary.<br> $370 for 12 ft2

valentina_108 [34]

Answer:

30.80

Step-by-step explanation:

$370/12ft^2

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3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago

Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

tatyana61 [14]

B is your correct answer.

7 0

3 years ago

What is G if B = A × (1+G)T and B = 3,455, A = 1,969, and T = 8? Answer as a rate in decimal format so that 12.34% would be ente

zubka84 [21]

Answer:

G=0.0728

Step-by-step explanation:

The expression given is:

$B=A*(1+G)^T$

This expression has the format of a compounded interest at a rate G for a time T. If B = 3,455, A = 1,969, and T = 8, the value of the rate G is determined by:

$3,455=1,969*(1+G)^8\\G = \sqrt[8]{\frac{3,455}{1,969}}-1\\G=0.0728$

The rate G is 0.0728.

7 0

3 years ago