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Arisa [49]
3 years ago
8

Can somebody tell me how to do this?

Mathematics
1 answer:
valentinak56 [21]3 years ago
7 0
I'm pretty sure that 20 is 5 but other than that, I can't help with anymore.
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If a graph of a system of two equations shows two lines that coincide on a coordinate plane, how many solutions does the system
olga55 [171]

If a graph of a system of two equations shows two lines that coincide on a coordinate plan there would be C.)Infinitely many solutions

I hope this helps, have a great day.

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS ASAP, I WILL BE GIVING YOU A THANKS!
densk [106]

Answer:

I would say D. There is no logical explanation for the final answer but there is for everything else.

For A: Makes sense because 3x-2 are in parenthesis outside a number so you can multiply.

For B: Makes sense because you are allowed to add/subtract like terms but in this case only subtracting would make sense, (which is what they did) since you want to get all the like terms on one side.

For C: Makes sense because you are trying to simplify the equation, and they are both like terms (they are both numbers that have no letter attached to them) and they are on the opposite side making them able to be simplified.

For D: No idea what the point is.

7 0
2 years ago
A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o
kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0
3 years ago
Which set of ordered pairs that satisfy the equation
krok68 [10]

Answer:

3

Step-by-step explanation:

3

5 0
3 years ago
Please help Let f(x)=2x^2+x-3 and g(x)=x-1. Perform the indicated operation, then find the domain. (F-g)(x)
Vesna [10]
F(x) = 2x² + x - 3
g(x) = x - 1
(f - g)(x) = (2x² + x - 3) - (x - 1)
(f - g)(x) = 2x² + (x - x) + (-3 + 1)
(f - g)(x) = 2x² - 2

The answer is D.
4 0
3 years ago
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