Answer:
( 3x + 5y) • (3x - 5y)
Step-by-step explanation:
hope this helps:))
ANSWER
D.

EXPLANATION
The given function is

Comparing to the general form of a trigonometric sine function,


The amplitude is absolute value of A


The period is given by



is a shift to the right of 4 units.
and

is an upward shift of 9 units
Therefore the phase shift is (4,9).
The correct answer is D
Answer:
The answer is 1 1/10
Step-by-step explanation:
To convert an improper fraction to a mixed fraction, follow these steps:
1. Divide the numerator by the denominator.
2. Write down the whole number answer.
3. Then write down any remainder above the denominator.
Answer:
I cannot understand your question
Make it more clear
so hmmm is compound interest, now, we'll be assuming the compounding period is per year, or annually, so it happens once per year.
